tìm x a,1/3-(1/2-X)=1/5 b,2/3-(1/2-X x 1/3=1/4 c,5/2-(1/3+X x 1/2=1 (x là nhân nhé) 06/09/2021 Bởi Athena tìm x a,1/3-(1/2-X)=1/5 b,2/3-(1/2-X x 1/3=1/4 c,5/2-(1/3+X x 1/2=1 (x là nhân nhé)
a,1/3-(1/2-X)=1/5 ⇔ 1/2 – X = 1/3 – 1/5 ⇔ 1/2 – X = 2/15 ⇔ X = 1/2 – 2/15 ⇔ X = 11/30 b,2/3-(1/2-X x 1/3)=1/4 ⇔ 1/2 – X × 1/3 = 2/3 – 1/4 ⇔ 1/2 – X × 1/3 = 5/12 ⇔ X × 1/3 = 1/2 – 5/12 ⇔ X × 1/3 = 1/12 ⇔ X = 1/12 : 1/3 ⇔ X = 1/4 c,5/2-(1/3+X x 1/2)=1 ⇔1/3 + X × 1/2 = 5/2 – 1 ⇔1/3 + X × 1/2 = 3/2 ⇔ X × 1/2 = 3/2 – 1/3 ⇔ X × 1/2 = 7/6 ⇔ X = 7/6 :1/2 ⇔ X = 7/3 Bình luận
Đáp án:
Giải thích các bước giải:
$@kinh0908$
a,1/3-(1/2-X)=1/5
⇔ 1/2 – X = 1/3 – 1/5
⇔ 1/2 – X = 2/15
⇔ X = 1/2 – 2/15
⇔ X = 11/30
b,2/3-(1/2-X x 1/3)=1/4
⇔ 1/2 – X × 1/3 = 2/3 – 1/4
⇔ 1/2 – X × 1/3 = 5/12
⇔ X × 1/3 = 1/2 – 5/12
⇔ X × 1/3 = 1/12
⇔ X = 1/12 : 1/3
⇔ X = 1/4
c,5/2-(1/3+X x 1/2)=1
⇔1/3 + X × 1/2 = 5/2 – 1
⇔1/3 + X × 1/2 = 3/2
⇔ X × 1/2 = 3/2 – 1/3
⇔ X × 1/2 = 7/6
⇔ X = 7/6 :1/2
⇔ X = 7/3