Tìm x a, x^2 – x = 0 b, x^2 – 6x + 8 = 0 c, x^2 – 3x = 0 21/11/2021 Bởi aikhanh Tìm x a, x^2 – x = 0 b, x^2 – 6x + 8 = 0 c, x^2 – 3x = 0
a)x^2-x=0 =>x(x-1)=0 =>x=0 x-1=0 -> x=1 b)x^2-6x+8=0 =>(x-2)(x-4)=0 =>x-2=0 -> x=2 x-4=0 -> x=4 c)x^2-3x=0 =>x(x-3)=0 =>x=0 x-3=0 -> x=3 Bình luận
Giải thích: A,`x^2-x=0` `=>x(x-1)=0` `=>x=0` ` x-1=0 -> x=1` B,`x^2-6x+8=0` `=>(x-2)(x-4)=0` `=>x-2=0 -> x=2` `x-4=0 -> x=4` C,`x^2-3x=0` `=>x(x-3)=0` `=>x=0` `x-3=0 -> x=3` `text{Học tốt!!!}` Bình luận
a)x^2-x=0
=>x(x-1)=0
=>x=0
x-1=0 -> x=1
b)x^2-6x+8=0
=>(x-2)(x-4)=0
=>x-2=0 -> x=2
x-4=0 -> x=4
c)x^2-3x=0
=>x(x-3)=0
=>x=0
x-3=0 -> x=3
Giải thích:
A,`x^2-x=0`
`=>x(x-1)=0`
`=>x=0`
` x-1=0 -> x=1`
B,`x^2-6x+8=0`
`=>(x-2)(x-4)=0`
`=>x-2=0 -> x=2`
`x-4=0 -> x=4`
C,`x^2-3x=0`
`=>x(x-3)=0`
`=>x=0`
`x-3=0 -> x=3`
`text{Học tốt!!!}`