tìm x a/(2x ²-3x)=0 b/4+3x ²/x-3 – 2x+2x ²/x-3 + 2x-13/x-3 =0 càn gấp

By Lydia

tìm x
a/(2x ²-3x)=0
b/4+3x ²/x-3 – 2x+2x ²/x-3 + 2x-13/x-3 =0
càn gấp

0 bình luận về “tìm x a/(2x ²-3x)=0 b/4+3x ²/x-3 – 2x+2x ²/x-3 + 2x-13/x-3 =0 càn gấp”

  1. a) $2x^2-3x=0$

    $⇔x.(2x-3)=0$

    $⇔$\(\left[ \begin{array}{l}x=0\\2x-3=0\end{array} \right.\) 

    $⇔$\(\left[ \begin{array}{l}x=0\\2x=3\end{array} \right.\) 

    $⇔$\(\left[ \begin{array}{l}x=0\\x=\dfrac{3}{2}\end{array} \right.\) 

    b) $\dfrac{4+3x^2}{x-3}-\dfrac{2x+2x^2}{x-3}+\dfrac{2x-13}{x-3}=0$

    $⇔\dfrac{4+3x^2-2x-2x^2+2x-13}{x-3}=0$

    $⇔\dfrac{x^2-9}{x-3}=0$

    $⇔\dfrac{(x-3)(x+3)}{x-3}=0$

    $⇔x+3=0$

    $⇔x=-3$

    Trả lời
  2. Đáp án:

    `a) 2x^2-3x=0`

    `⇒ x.(2x-3)=0`

    `⇒` \(\left[ \begin{array}{l}x=0\\2x-3=0\end{array} \right.\) 

    `⇒`\(\left[ \begin{array}{l}x=0\\2x=3\end{array} \right.\) 

    `⇒`\(\left[ \begin{array}{l}x=0\\x=\dfrac{3}{2}\end{array} \right.\) 

    `b)(4+3x^2)/(x-3)-(2x+2x^2)/(x-3)+(2x-13)/(x-3)=0`

    `⇒ (4+3x^2-2x-2x^2+2x-13)/(x-3)=0`

    `⇒ (x^2-9)/(x-3)=0`

    `⇒((x-3)(x+3))/(x-3)=0`

    `⇒x+3=0`

    `⇒x=-3`

     

    Trả lời

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