Tìm x
a) 3/2 – ( x- 7/3)= giá trị tuyệt đối của -3/4 – 9/8
b) 5/2 – ( 3/2-7/3+x)= 8/15- ( 1/4-7/10)
c) 3( 1/2-x ) +1/3= 7/6-x
d) 1/2 ( x-3)+2/7 * ( 7x-4) = 10
Tìm x
a) 3/2 – ( x- 7/3)= giá trị tuyệt đối của -3/4 – 9/8
b) 5/2 – ( 3/2-7/3+x)= 8/15- ( 1/4-7/10)
c) 3( 1/2-x ) +1/3= 7/6-x
d) 1/2 ( x-3)+2/7 * ( 7x-4) = 10
$a$) `3/2 – (x – 7/3) = |-3/4 – 9/8|`
`⇔ 3/2 – (x – 7/3 ) = 15/8`
`⇔ x – 7/3 =-3/8`
`⇔ x = 47/24`
Vậy `x=47/24`
$b$) `5/2 – (3/2 – 7/3 + x) = 8/15 – (1/4 – 7/10)`
`⇔ 5/2 – 3/2 + 7/3 – x = 8/15 – 1/4 + 7/10`
`⇔ 1 + 7/3 – x = 59/60`
`⇔ x = 47/20`
Vậy `x=47/20`
$c$) `3(1/2 – x) + 1/3 = 7/6 – x`
`⇔ 3/2 – 3x + 1/3 = 7/6 – x`
`⇔ -2x = 7/6 – 1/3 – 3/2`
`⇔ -2x = -2/3`
`⇔ x = 1/3`
Vậy `x=1/3`
$d$) `1/2 (x-3) + 2/7 . (7x -4) = 10`
`⇔ 1/2 . x – 3/2 + 2x – 8/7 = 10`
`⇔ 5/2 . x = 177/14`
`⇔ x = 177/35`
Vậy `x=177/35`
a) $\dfrac{3}{2}-(x-\dfrac{7}{3})=|-\dfrac{3}{4}-\dfrac{9}{8}|$
$\dfrac{3}{2}-(x-\dfrac{7}{3})=\dfrac{15}{8}$
$x-\dfrac{7}{3}=\dfrac{3}{2}-\dfrac{15}{8}$
$x-\dfrac{7}{3}=-\dfrac{3}{8}$
$⇒x=-\dfrac{3}{8}+\dfrac{7}{3}=\dfrac{47}{24}$
b) $\dfrac{5}{2}-(\dfrac{3}{2}-\dfrac{7}{3}+x)=\dfrac{8}{15}-(\dfrac{1}{4}-\dfrac{7}{10})$
$\dfrac{5}{2}-(-\dfrac{5}{6}+x)=\dfrac{8}{15}+\dfrac{9}{20}=\dfrac{59}{60}$
$-\dfrac{5}{6}+x=\dfrac{5}{2}-\dfrac{59}{60}=\dfrac{91}{60}$
$x=\dfrac{91}{60}+\dfrac{5}{6}=\dfrac{47}{20}$
$⇒x=\dfrac{59}{60}-\dfrac{10}{3}=-\dfrac{47}{20}$
c) $3.(\dfrac{1}{2}-x)+\dfrac{1}{3}=\dfrac{7}{6}-x$
$\dfrac{3}{2}-3x+\dfrac{1}{3}-\dfrac{7}{6}+x=0$
$(\dfrac{3}{2}-\dfrac{7}{6}+\dfrac{1}{3})+(-3x+x)=0$
$\dfrac{2}{3}-2x=0$
$2x=\dfrac{2}{3}$
$⇒x=\dfrac{2}{3}:2=\dfrac{1}{3}$
d) $\dfrac{1}{2}(x-3)+\dfrac{2}{7}.(7x-4)=10$
$\dfrac{1}{2}x-\dfrac{3}{2}+2x-\dfrac{8}{7}=10$
$(\dfrac{1}{2}x+2x)+(-\dfrac{3}{2}-\dfrac{8}{7})=10$
$\dfrac{5}{2}x-\dfrac{37}{14}=10$
$\dfrac{5}{2}x=10+\dfrac{37}{14}=\dfrac{177}{14}$
$x=\dfrac{177}{14}:\dfrac{5}{2}=\dfrac{177}{35}$