Tìm x a) 3/2 – ( x- 7/3)= giá trị tuyệt đối của -3/4 – 9/8 b) 5/2 – ( 3/2-7/3+x)= 8/15- ( 1/4-7/10) c) 3( 1/2-x ) +1/3= 7/6-x d) 1/2 ( x-3)+2/7 * ( 7

0 bình luận về “Tìm x a) 3/2 – ( x- 7/3)= giá trị tuyệt đối của -3/4 – 9/8 b) 5/2 – ( 3/2-7/3+x)= 8/15- ( 1/4-7/10) c) 3( 1/2-x ) +1/3= 7/6-x d) 1/2 ( x-3)+2/7 * ( 7”

1. a) $\frac{3}{2}$  – ( x- $\frac{7}{3}$ )=  |$\frac{-3}{4}$  – $\frac{9}{8}$ |

   ⇔ $\frac{3}{2}$  – ( x- $\frac{7}{3}$ )= $\frac{15}{8}$ 

   ⇔x- $\frac{7}{3}$ = -$\frac{3}{8}$ 

   ⇔ x = $\frac{47}{24}$ 

   b) $\frac{5}{2}$  – ( $\frac{3}{2}$ – $\frac{7}{3}$ +x)= $\frac{8}{15}$  – ( $\frac{1}{4}$ – $\frac{7}{10}$ )

   ⇔ $\frac{5}{2}$  –  $\frac{3}{2}$ + $\frac{7}{3}$ – x = $\frac{8}{15}$  – $\frac{1}{4}$ + $\frac{7}{10}$

   ⇔ – x = $\frac{8}{15}$  – $\frac{1}{4}$ + $\frac{7}{10}$ – $\frac{5}{2}$  +  $\frac{3}{2}$ – $\frac{7}{3}$

   ⇔ -x = –$\frac{47}{20}$

   ⇔ x = $\frac{47}{20}$

   c) 3($\frac{1}{2}$ – x ) + $\frac{1}{3}$ = $\frac{7}{6}$ -x

   ⇔ $\frac{3}{2}$ – 3x + $\frac{1}{3}$ = $\frac{7}{6}$ -x

   ⇔ -3x + x = $\frac{7}{6}$ – $\frac{3}{2}$ – $\frac{1}{3}$

   ⇔ – 2x = -$\frac{2}{3}$

   ⇔ x = $\frac{1}{3}$

   d) $\frac{1}{2}$ * ( x-3)+ $\frac{2}{7}$ * ( 7x-4) = 10

   ⇔ $\frac{1}{2}$x – $\frac{3}{2}$ + 2x – $\frac{8}{7}$ = 10

   ⇔ $\frac{1}{2}$x + 2x = 10 + $\frac{8}{7}$ + $\frac{3}{2}$

   ⇔ $\frac{5}{2}$x = $\frac{177}{14}$

   ⇔ x = $\frac{177}{35}$

    

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2. Đáp án:

    

   Giải thích các bước giải:

    

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