Tìm x: A) x⁶⁰=x⁵⁰ B)x¹⁸:128=x¹¹ C)180-(50:x+10):3=175

Đáp án:

a, \(\left[ \begin{array}{l}x=0\\x=±1\end{array} \right.\)

b, \(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\) 

c, `x=10`

Giải thích các bước giải:

a, `x^60=x^50`

`<=> x^60-x^60=0`

`<=> x^50.(x^10-1)=0`

`<=>` \(\left[ \begin{array}{l}x=0\\x=±1\end{array} \right.\)

Vậy: …

b, `x^18:128=x^11`

`<=> x^18-128.x^11=0`

`<=> x^11.(x^7-128)=0`

`<=>` \(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\) 

Vậy: …

c, `180-\frac{50:x+10}{3}=175`

`<=> 540-(50:x+10)=525`

`<=> 540-\frac{50+10x}{x}=525`

`<=> \frac{540x}{x}-\frac{50+10x}{x}=525`

`<=> \frac{540x-50-10x}{x}=525`

`<=> -50+530x=525x`

`<=> -50+530x-525x=0`

`<=> -50+5x=0`

`<=> 5x=50`

`<=> x=10`

Vậy: …