Tìm a biết a : 2 x 5 + a : 3 x 4 – a : 5 x 8 + a : 100 x 35 = 2010 11/07/2021 Bởi Lydia Tìm a biết a : 2 x 5 + a : 3 x 4 – a : 5 x 8 + a : 100 x 35 = 2010
`a : 2 × 5 + a : 3 × 4 – a : 5 ×8 + a : 100× 35 = 2010` `⇔a×(5/2 +4/3-8/5+(35)/(100))= 2010` `⇔a×(31)/(12)= 2010` `⇔a=(24120)/(31)` Bình luận
`a : 2 xx 5 + a : 3 xx 4 – a : 5 xx 8 + a : 100 xx 35 = 2010` `a xx 5/2 + a xx 4/3 – a xx 8/5 + a xx 7/20 = 2010` `a xx (5/2 + 4/3 – 8/5 + 7/20) = 2010` `a xx 31/12 = 2010` `a = 2010 : 31/12` `a = 2010 xx 12/31` `a = 24120/31` Vậy `x = 24120/31` Bình luận
`a : 2 × 5 + a : 3 × 4 – a : 5 ×8 + a : 100× 35 = 2010`
`⇔a×(5/2 +4/3-8/5+(35)/(100))= 2010`
`⇔a×(31)/(12)= 2010`
`⇔a=(24120)/(31)`
`a : 2 xx 5 + a : 3 xx 4 – a : 5 xx 8 + a : 100 xx 35 = 2010`
`a xx 5/2 + a xx 4/3 – a xx 8/5 + a xx 7/20 = 2010`
`a xx (5/2 + 4/3 – 8/5 + 7/20) = 2010`
`a xx 31/12 = 2010`
`a = 2010 : 31/12`
`a = 2010 xx 12/31`
`a = 24120/31`
Vậy `x = 24120/31`