Tìm x: a, $\frac{3}{4}$ × (x+1)=$\frac{4}{5}$ b, $\frac{1}{8}$ ÷ (x-1)= $\frac{1}{4}$

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1. Đáp án:

   `a) 3/4×(x+1)=4/5`

   `<=>(x+1)=4/5:3/4`

   `<=>x+1=16/15`

   `<=>x=16/15-1`

   `<=>x=1/15`

   `b)1/8:(x-1)=1/4`

   `<=>x-1=1/8:1/4`

   `<=>x-1/1/2`

   `<=>x=1/2+1`

   `<=>x=3/2`

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2. Cho mk ctlhn nhé!

   a, $\frac{3}{4}$ ×(x+1) = $\frac{4}{5}$

   ⇔ x+1= $\frac{4}{5}$ ÷ $\frac{3}{4}$ 

   ⇔ x+1= $\frac{16}{15}$ 

   ⇔ x= $\frac{16}{15}$ – 1 = $\frac{1}{15}$

         Vậy x= $\frac{1}{15}$

   b, $\frac{1}{8}$ ÷ (x-1)= $\frac{1}{4}$

   ⇔ x-1 = $\frac{1}{8}$ ÷ $\frac{1}{4}$ 

   ⇔ x-1 = $\frac{1}{2}$

   ⇔ x = $\frac{1}{2}$ +1 = $\frac{3}{2}$

        Vậy x = $\frac{3}{2}$  

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