tìm x .a,x mũ 3 = -27. b, ( 2x-1) mũ 3 = 8. c, ( x- 2 ) mũ 2= 16 . d, ( 2x – 3 ) mũ 2 = 9. e, ( 2x- 1 ) mũ 4 = 81. f, ( x-1 ) mũ 5 = -32. g, ( x- 2 ) mũ 2 = 1. h, ( 4x-3 ) mũ 3 = -125
tìm x .a,x mũ 3 = -27. b, ( 2x-1) mũ 3 = 8. c, ( x- 2 ) mũ 2= 16 . d, ( 2x – 3 ) mũ 2 = 9. e, ( 2x- 1 ) mũ 4 = 81. f, ( x-1 ) mũ 5 = -32. g, ( x- 2 )
By Serenity
`a) => x^3=(-3)^3`
`=> x=-3`
`b) => (2x-1)^3=2^3`
`=> 2x-1=2`
`=> 2x=3`
`=> x=3/2`
`c) => (x-2)^2=±4^2`
`=> x-2=4` hoặc `x-2=-4`
`=> x=6` hoặc `x=-2`
`d) => (2x-3)^2=±3^2`
`=> 2x-3=3` hoặc `2x-3=-3`
`=> 2x=6` hoặc `2x=0`
`=> x=3` hoặc `x=0`
`e) => (2x-1)^4=±3^4`
`=> 2x-1=3` hoặc `2x-1=-3`
`=> 2x=4` hoặc `x=-2`
`=> x=2` hoặc `x=-1`
`f) => (x-1)^5=(-2)^5`
`=> x-1=-2`
`=> x=-1`
`g) => (x-1)^2=±1^2`
`=> x-1=1` hoặc `x-1=-1`
`=> x=2` hoặc `x=0`
`h) => (4x-3)^3=(-5)^3`
`=> 4x-3=-5`
`=> 4x=-2`
`=> x=-1/2`
a, `x^3` = -27
=> `x^3` = `(-3)^3`
=> x = -3
b, `( 2x-1)^3` = 8
=> `(2x-1)^3` = `2^3`
=> 2x-1 = 2
=> 2x = 3
=> x= `3/2`
c, `(x- 2)^2` = 16
=> `(x- 2)^2` = `4^2`
=> x – 2 = 4 hoặc x – 2 = -4
=> x = 6 hoặc x = -2
d, `(2x – 3)^2` = 9.
=> `(2x – 3)^2` = `3^2`
=> 2x – 3 = 3
=> 2x = 6
=> x = 3
e, `(2x- 1)^4` = 81
=> `(2x- 1)^4` = `3^4`
=> 2x – 1 =3
=> 2x = 4
=> x = 2
f, `(x – 1)^5` = -32
=> `(x – 1)^5` = `(-2)^5`
=> x – 1 = -2
=> x = -1
g, `( x- 2 )^2` = 1
=> x- 2 = 1 hoặc x – 2 = -1
= >x = 3 hoặc 1
h, `( 4x – 3 )^3` = -125
=> `( 4x – 3 )^3` = `(-5)^3`
=> 4x – 3 = – 5
=> 4x = -2
=> x = `-1/2`
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