Tìm x b) | -4/27 | – 1 và 1/3 . x = 2/9 ( 1 và 1/3 là hỗ số ) c) ( 1/4 – x )^2 -125% = 1 và 13/16 20/08/2021 Bởi Liliana Tìm x b) | -4/27 | – 1 và 1/3 . x = 2/9 ( 1 và 1/3 là hỗ số ) c) ( 1/4 – x )^2 -125% = 1 và 13/16
Đáp án: `b,` `|-4/27|-1 1/3x=2/9` `=>4/27-4/3x=2/9` `=>4/3x=4/27-2/9` `=>4/3x=-2/27` `=>x=-1/18` Vậy `x=-1/18` `c,` `(1/4-x)^2-125%=1 13/16` `=>(1/4-x)^2-5/4=29/16` `=>(1/4-x)^2=29/16+5/4` `=>(1/4-x)^2=49/16=(7/4)^2` `=>` \(\left[ \begin{array}{l}\dfrac{1}{4}-x=\dfrac{7}{4}\\\dfrac{1}{4}-x=-\dfrac{7}{4}\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{1}{4}-\dfrac{7}{4}\\x=\dfrac{1}{4}-(-\dfrac{7}{4})\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=-\dfrac{3}{2}\\x=2\end{array} \right.\) Vậy `x\in{2;-3/2}` Bình luận
Lời giải: b, `|-4/27| – 1 1/3 . x = 2/9` `⇒ 4/27 – 4/3 . x = 2/9` `⇒ 4/3 . x = 4/27 – 2/9` `⇒ 4/3 . x = 4/27 – 6/27` `⇒ 4/3 . x = -2/27` `⇒ x = -2/27 : 4/3` `⇒ x = -2/27 . 3/4` `⇒ x = -1/18` Vậy `x = -1/18`. c, `(1/4 – x)^2 – 125% = 1 13/16` `⇒ (1/4 – x)^2 – 5/4 = 29/16` `⇒ (1/4 – x)^2 = 29/16 + 5/4` `⇒ (1/4 – x)^2 = 29/16 + 20/16` `⇒ (1/4 – x)^2 = 49/16` `⇒ (1/4 – x)^2 = (7/4)^2 = ((-7)/4)^2` `⇒ 1/4 – x = 7/4` hoặc `1/4 – x = (-7)/4` `⇒ x = 1/4 – 7/4 = -3/2` hoặc `x = 1/4 + 7/4 = 8/4 = 2` Vậy `x ∈ { -3/2 ; 2 }`. Bình luận
Đáp án:
`b,`
`|-4/27|-1 1/3x=2/9`
`=>4/27-4/3x=2/9`
`=>4/3x=4/27-2/9`
`=>4/3x=-2/27`
`=>x=-1/18`
Vậy `x=-1/18`
`c,`
`(1/4-x)^2-125%=1 13/16`
`=>(1/4-x)^2-5/4=29/16`
`=>(1/4-x)^2=29/16+5/4`
`=>(1/4-x)^2=49/16=(7/4)^2`
`=>` \(\left[ \begin{array}{l}\dfrac{1}{4}-x=\dfrac{7}{4}\\\dfrac{1}{4}-x=-\dfrac{7}{4}\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{1}{4}-\dfrac{7}{4}\\x=\dfrac{1}{4}-(-\dfrac{7}{4})\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=-\dfrac{3}{2}\\x=2\end{array} \right.\)
Vậy `x\in{2;-3/2}`
Lời giải:
b, `|-4/27| – 1 1/3 . x = 2/9`
`⇒ 4/27 – 4/3 . x = 2/9`
`⇒ 4/3 . x = 4/27 – 2/9`
`⇒ 4/3 . x = 4/27 – 6/27`
`⇒ 4/3 . x = -2/27`
`⇒ x = -2/27 : 4/3`
`⇒ x = -2/27 . 3/4`
`⇒ x = -1/18`
Vậy `x = -1/18`.
c, `(1/4 – x)^2 – 125% = 1 13/16`
`⇒ (1/4 – x)^2 – 5/4 = 29/16`
`⇒ (1/4 – x)^2 = 29/16 + 5/4`
`⇒ (1/4 – x)^2 = 29/16 + 20/16`
`⇒ (1/4 – x)^2 = 49/16`
`⇒ (1/4 – x)^2 = (7/4)^2 = ((-7)/4)^2`
`⇒ 1/4 – x = 7/4` hoặc `1/4 – x = (-7)/4`
`⇒ x = 1/4 – 7/4 = -3/2` hoặc `x = 1/4 + 7/4 = 8/4 = 2`
Vậy `x ∈ { -3/2 ; 2 }`.