Tìm x, biết: x+2014/2 + 2x+4028/7 = x+2014/5 + x+2014/6 Giúp mik với 03/08/2021 Bởi Delilah Tìm x, biết: x+2014/2 + 2x+4028/7 = x+2014/5 + x+2014/6 Giúp mik với
$\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2014}{5}+\dfrac{x+2014}{6}$ $\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}-\dfrac{x+2014}{5}-\dfrac{x+2014}{6}$ $(x+2014).(\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6})=0$ Vì $\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6}>0$ $→x+2014=0$ $→x=-2014$ Vậy $x=-2014$ Bình luận
`(x + 2014)/2 + (2x + 4028)/7 = (x + 2014)/5+ (x+2014)/6` ⇒ `(x + 2014)/2 + (2x + 4028)/7 – (x + 2014)/5 – (x+2014)/6` = 0 ⇒ `(x + 2014)/2 + (2.(x+2014))/7 – (x + 2014)/5 – (x+2014)/6` = 0 ⇒` (x + 2014 ) . (1/2 + 2/7 – 1/5 – 1/6 ) = 0` ⇔ x + 2014 = 0 (do ` 1/2 + 2/7 – 1/5 – 1/6 ` $\neq$ 0` ⇔ x = -2014 Bình luận
$\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2014}{5}+\dfrac{x+2014}{6}$
$\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}-\dfrac{x+2014}{5}-\dfrac{x+2014}{6}$
$(x+2014).(\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6})=0$
Vì $\dfrac{1}{2}+\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{1}{6}>0$
$→x+2014=0$
$→x=-2014$
Vậy $x=-2014$
`(x + 2014)/2 + (2x + 4028)/7 = (x + 2014)/5+ (x+2014)/6`
⇒ `(x + 2014)/2 + (2x + 4028)/7 – (x + 2014)/5 – (x+2014)/6` = 0
⇒ `(x + 2014)/2 + (2.(x+2014))/7 – (x + 2014)/5 – (x+2014)/6` = 0
⇒` (x + 2014 ) . (1/2 + 2/7 – 1/5 – 1/6 ) = 0`
⇔ x + 2014 = 0
(do ` 1/2 + 2/7 – 1/5 – 1/6 ` $\neq$ 0`
⇔ x = -2014