Tìm x, biết -3/5.x=1/4+0,75 c) (1/7−1/3).x=28/3.(1/4−1/7) d) 5/7.x=9/8−0,125 e)(2/11+1/3).x=(1/7−1/8).5/6 08/11/2021 Bởi Savannah Tìm x, biết -3/5.x=1/4+0,75 c) (1/7−1/3).x=28/3.(1/4−1/7) d) 5/7.x=9/8−0,125 e)(2/11+1/3).x=(1/7−1/8).5/6
Đáp án: BẠN THAM KHẢO NHA! Giải thích các bước giải: $a, \dfrac{-3}{5}.x=\dfrac{1}{4}+0,75$ $=> \dfrac{-3}{5}.x=1$ $=> x=-1.\dfrac{5}{3}=-\dfrac{5}{3}$ $b, (\dfrac{1}{7}-\dfrac{1}{3}).x=\dfrac{28}{3}.(\dfrac{1}{4}-\dfrac{1}{7})$ $=> x=-1.\dfrac{21}{4}=-\dfrac{21}{4}$ $c, \dfrac{5}{7}x=\dfrac{9}{8}-0,125$ $=> \dfrac{5}{7}x=1$ $=> x=\dfrac{7}{5}$ $d, (\dfrac{2}{11}+\dfrac{1}{3})x=(\dfrac{1}{7}-\dfrac{1}{8}).\dfrac{5}{6}$ $=> \dfrac{17}{33}x=\dfrac{5}{336}$ $=> x=\dfrac{55}{1904}$ Bình luận
a, $\frac{-3}{5}$x = $\frac{1}{4}$ + 0,75 ⇔$\frac{-3}{5}$x = $\frac{1}{4}$ + $\frac{3}{4}$ ⇔$\frac{-3}{5}$x = 1 ⇔x = 1: $\frac{-3}{5}$ ⇔x = $\frac{-5}{3}$ KL: x = $\frac{-5}{3}$ c, ($\frac{1}{7}$ – $\frac{1}{2}$)x = $\frac{28}{3}$( $\frac{1}{4}$ – $\frac{1}{7}$ ⇔$\frac{-4}{21}$x = $\frac{28}{3}$. $\frac{3}{28}$ ⇔$\frac{-4}{21}$x = 1 ⇔x = 1 : $\frac{-4}{21}$ ⇔x = $\frac{-21}{4}$ KL: …. d, $\frac{5}{7}$x = $\frac{9}{8}$ – 0,125 ⇔$\frac{5}{7}$x = $\frac{9}{8}$ – $\frac{1}{8}$ ⇔$\frac{5}{7}$x = 1 ⇔x = $\frac{7}{5}$ KL: …. e, ($\frac{2}{11}$ + $\frac{1}{3}$)x = ( $\frac{1}{7}$ – $\frac{1}{8}$) $\frac{5}{6}$ ⇔$\frac{17}{33}$x = $\frac{5}{336}$ ⇔x = $\frac{55}{1904}$ KL: …. Bình luận
Đáp án:
BẠN THAM KHẢO NHA!
Giải thích các bước giải:
$a, \dfrac{-3}{5}.x=\dfrac{1}{4}+0,75$
$=> \dfrac{-3}{5}.x=1$
$=> x=-1.\dfrac{5}{3}=-\dfrac{5}{3}$
$b, (\dfrac{1}{7}-\dfrac{1}{3}).x=\dfrac{28}{3}.(\dfrac{1}{4}-\dfrac{1}{7})$
$=> x=-1.\dfrac{21}{4}=-\dfrac{21}{4}$
$c, \dfrac{5}{7}x=\dfrac{9}{8}-0,125$
$=> \dfrac{5}{7}x=1$
$=> x=\dfrac{7}{5}$
$d, (\dfrac{2}{11}+\dfrac{1}{3})x=(\dfrac{1}{7}-\dfrac{1}{8}).\dfrac{5}{6}$
$=> \dfrac{17}{33}x=\dfrac{5}{336}$
$=> x=\dfrac{55}{1904}$
a, $\frac{-3}{5}$x = $\frac{1}{4}$ + 0,75
⇔$\frac{-3}{5}$x = $\frac{1}{4}$ + $\frac{3}{4}$
⇔$\frac{-3}{5}$x = 1
⇔x = 1: $\frac{-3}{5}$
⇔x = $\frac{-5}{3}$
KL: x = $\frac{-5}{3}$
c, ($\frac{1}{7}$ – $\frac{1}{2}$)x = $\frac{28}{3}$( $\frac{1}{4}$ – $\frac{1}{7}$
⇔$\frac{-4}{21}$x = $\frac{28}{3}$. $\frac{3}{28}$
⇔$\frac{-4}{21}$x = 1
⇔x = 1 : $\frac{-4}{21}$
⇔x = $\frac{-21}{4}$
KL: ….
d, $\frac{5}{7}$x = $\frac{9}{8}$ – 0,125
⇔$\frac{5}{7}$x = $\frac{9}{8}$ – $\frac{1}{8}$
⇔$\frac{5}{7}$x = 1
⇔x = $\frac{7}{5}$
KL: ….
e, ($\frac{2}{11}$ + $\frac{1}{3}$)x = ( $\frac{1}{7}$ – $\frac{1}{8}$) $\frac{5}{6}$
⇔$\frac{17}{33}$x = $\frac{5}{336}$
⇔x = $\frac{55}{1904}$
KL: ….