Tìm x biết: (4/3x- căn 0,25) (|x-1|-1/2)=0 03/09/2021 Bởi Peyton Tìm x biết: (4/3x- căn 0,25) (|x-1|-1/2)=0
Đáp án: \(\left[ \begin{array}{l}x = \dfrac{8}{3}\\x = \dfrac{3}{2}\\x = \dfrac{1}{2}\end{array} \right.\) Giải thích các bước giải: \(\begin{array}{l}\left( {\dfrac{4}{{3x}} – \sqrt {0,25} } \right)\left( {\left| {x – 1} \right| – \dfrac{1}{2}} \right) = 0\\\left( {\dfrac{4}{{3x}} – \dfrac{1}{2}} \right)\left( {\left| {x – 1} \right| – \dfrac{1}{2}} \right) = 0\\ \to \left[ \begin{array}{l}\dfrac{4}{{3x}} – \dfrac{1}{2} = 0\\\left| {x – 1} \right| – \dfrac{1}{2} = 0\end{array} \right.\\ \to \left[ \begin{array}{l}\dfrac{4}{{3x}} = \dfrac{1}{2}\\x – 1 = \dfrac{1}{2}\\x – 1 = – \dfrac{1}{2}\end{array} \right.\\ \to \left[ \begin{array}{l}x = \dfrac{8}{3}\\x = \dfrac{3}{2}\\x = \dfrac{1}{2}\end{array} \right.\end{array}\) Bình luận
Đáp án:
\(\left[ \begin{array}{l}
x = \dfrac{8}{3}\\
x = \dfrac{3}{2}\\
x = \dfrac{1}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left( {\dfrac{4}{{3x}} – \sqrt {0,25} } \right)\left( {\left| {x – 1} \right| – \dfrac{1}{2}} \right) = 0\\
\left( {\dfrac{4}{{3x}} – \dfrac{1}{2}} \right)\left( {\left| {x – 1} \right| – \dfrac{1}{2}} \right) = 0\\
\to \left[ \begin{array}{l}
\dfrac{4}{{3x}} – \dfrac{1}{2} = 0\\
\left| {x – 1} \right| – \dfrac{1}{2} = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
\dfrac{4}{{3x}} = \dfrac{1}{2}\\
x – 1 = \dfrac{1}{2}\\
x – 1 = – \dfrac{1}{2}
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{8}{3}\\
x = \dfrac{3}{2}\\
x = \dfrac{1}{2}
\end{array} \right.
\end{array}\)