Tìm x, biết” a) x+1/10 + x+1/11 + x+1/120 = x+1/13 + x+1/14 b) (x+4/2000) + (x+3/2001) = (x+2/2002) + (x+1/2003) 31/08/2021 Bởi Savannah Tìm x, biết” a) x+1/10 + x+1/11 + x+1/120 = x+1/13 + x+1/14 b) (x+4/2000) + (x+3/2001) = (x+2/2002) + (x+1/2003)
a) x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14 x+1/10 + x+1/11 + x+1/12 – x+ 1/13 – x+1/14 = 0 ( x + 1). (1/10 + 1/11 + 1/12 – 1/13 – 1/14) = 0 Vì (1/10 + 1/11 + 1/12 – 1/13 – 1/14) ≠ 0 nên:x + 1 = 0x = −1Vậy x=-10 Bình luận
a) x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14 x+1/10 + x+1/11 + x+1/12 – x+ 1/13 – x+1/14 = 0 ( x + 1). (1/10 + 1/11 + 1/12 – 1/13 – 1/14) = 0 Vì (1/10 + 1/11 + 1/12 – 1/13 – 1/14) ≠ 0 nên:x + 1 = 0x = −1Vậy x=-10 Bình luận
a) x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
x+1/10 + x+1/11 + x+1/12 – x+ 1/13 – x+1/14 = 0
( x + 1). (1/10 + 1/11 + 1/12 – 1/13 – 1/14) = 0
Vì (1/10 + 1/11 + 1/12 – 1/13 – 1/14) ≠ 0 nên:
x + 1 = 0
x = −1
Vậy x=-10
a) x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14
x+1/10 + x+1/11 + x+1/12 – x+ 1/13 – x+1/14 = 0
( x + 1). (1/10 + 1/11 + 1/12 – 1/13 – 1/14) = 0
Vì (1/10 + 1/11 + 1/12 – 1/13 – 1/14) ≠ 0 nên:
x + 1 = 0
x = −1
Vậy x=-10