Tìm x, biết: a) 3x(12x – 4) – 9x(4x – 3) = 30 b) x(5 – 2x) + 2x(x – 1) = 15 06/08/2021 Bởi Serenity Tìm x, biết: a) 3x(12x – 4) – 9x(4x – 3) = 30 b) x(5 – 2x) + 2x(x – 1) = 15
$a.$ $3x(12x-4)- 9x(4x – 3) = 30$ $⇔36x^2-12x-36x^2+27x=30$ $⇔15x=30$ $⇔x=2$ Vậy $x=2$ $b.$ $x(5-2x) + 2x(x – 1) = 15$ $⇔5x-2x^2+2x^2-2x=15$ $⇔3x=15$ $⇔x=5$ Vậy $x=5$. Bình luận
Đáp án: a) 3x.(12x – 4) – 9x.(4x – 3) = 30 ⇔ 36x2 – 12x – 36x2 + 27x = 30 ⇔ 15x = 30 ⇔ x = 2. b) x (5 – 2x) + 2x (x – 1) = 15 ⇔ 5x – 2x2 + 2x2 – 2x = 15 ⇔ 3x = 15 ⇔ x =5 Bình luận
$a.$ $3x(12x-4)- 9x(4x – 3) = 30$
$⇔36x^2-12x-36x^2+27x=30$
$⇔15x=30$
$⇔x=2$
Vậy $x=2$
$b.$ $x(5-2x) + 2x(x – 1) = 15$
$⇔5x-2x^2+2x^2-2x=15$
$⇔3x=15$
$⇔x=5$
Vậy $x=5$.
Đáp án:
a) 3x.(12x – 4) – 9x.(4x – 3) = 30
⇔ 36x2 – 12x – 36x2 + 27x = 30
⇔ 15x = 30
⇔ x = 2.
b) x (5 – 2x) + 2x (x – 1) = 15
⇔ 5x – 2x2 + 2x2 – 2x = 15
⇔ 3x = 15
⇔ x =5