Tìm x , biết :
a) ( x + 7 )^2 – x ( x – 3 ) = 12
b) ( 2x + 3 )^2 – 4x^2 =10
Tìm x , biết : a) ( x + 7 )^2 – x ( x – 3 ) = 12 b) ( 2x + 3 )^2 – 4x^2 =10
By Gabriella
By Gabriella
Tìm x , biết :
a) ( x + 7 )^2 – x ( x – 3 ) = 12
b) ( 2x + 3 )^2 – 4x^2 =10
a)(x+7)²-x(x-3)=12
x²+14x+49-x²+3x=12
17x+49=12
17x=12-49
17x=-37
x=-37:17
x=$\frac{-37}{17}$
b)( 2x + 3 )²- 4x² =10
4x²+12x+9-4×2=10
12x+9=10
12x=10-9
12x=1
x=1:12
x=$\frac{1}{12}$
`a)(x+7)^2-x(x-3)=12.`
`⇒x^2+2.x.7+7^2-x.x-x.(-3)=12.`
`⇒x^2+14x+49-x^2+3x=12.`
`⇒(x^2-x^2)+(14x+3x)+49=12.`
`⇒17x+49=12.`
`⇒17x=12-49.`
`⇒17x=-37.`
`⇒x=-37/17.`
`b)(2x+3)^2-4x^2=10.`
`⇒(2x)^2+2.2x.3+3^2-4x^2=10.`
`⇒4x^2+2.2x.3+3^2-4x^2=10.`
`⇒4x^2+12x+9-4x^2=10.`
`⇒(4x^2-4x^2)+12x+9=10.`
`⇒12x+9=10.`
`⇒12x=10-9.`
`⇒12x=1.`
`⇒x=1/12.`