Toán Tìm x biết a) $\frac{2}{x+3}$ = $\frac{x+3}{16}$ 30/08/2021 By Adalynn Tìm x biết a) $\frac{2}{x+3}$ = $\frac{x+3}{16}$
Tham khảo ` \frac{2}{x+3}=\frac{x+3}{16}(x \ne -3)` `⇒(x+3)^2=32` `⇒x+3=±\sqrt{32}` `⇒`\(\left[ \begin{array}{l}x=\sqrt{32}-3\\x=-\sqrt{32}-3\end{array} \right.\) Vậy `x=\sqrt{32}-3` hoặc ` x=-\sqrt{32}-3` `\text{©CBT}` Trả lời
$\frac{2}{X+3}$ =$\frac{X+3}{16}$ ⇒ ( X+ 3 ) . ( X + 3) = 16.2 ⇒( X+ 3)² = 32 ⇒(x+3)²=4$\sqrt{2}$ ⇒(x+3)²=4$\sqrt{2}$ hoặc x+3= – 4$\sqrt[]{2}$ +) x + 3 4$\sqrt[]{2}$ ⇒ x= 4$\sqrt[]{2}$ – 3 +)x + 3 4$\sqrt[]{2}$ ⇒ x = -4$\sqrt[]{2}$ – 3 Vậy : x ∈ { 4$\sqrt[]{2}$ – 3 ; 4$\sqrt[]{2}$ – 3 # Come on in vietnam $rin^{cute}$ Trả lời
Tham khảo
` \frac{2}{x+3}=\frac{x+3}{16}(x \ne -3)`
`⇒(x+3)^2=32`
`⇒x+3=±\sqrt{32}`
`⇒`\(\left[ \begin{array}{l}x=\sqrt{32}-3\\x=-\sqrt{32}-3\end{array} \right.\)
Vậy `x=\sqrt{32}-3` hoặc ` x=-\sqrt{32}-3`
`\text{©CBT}`
$\frac{2}{X+3}$ =$\frac{X+3}{16}$
⇒ ( X+ 3 ) . ( X + 3) = 16.2
⇒( X+ 3)² = 32
⇒(x+3)²=4$\sqrt{2}$
⇒(x+3)²=4$\sqrt{2}$ hoặc x+3= – 4$\sqrt[]{2}$
+) x + 3 4$\sqrt[]{2}$
⇒ x= 4$\sqrt[]{2}$ – 3
+)x + 3 4$\sqrt[]{2}$
⇒ x = -4$\sqrt[]{2}$ – 3
Vậy : x ∈ { 4$\sqrt[]{2}$ – 3 ; 4$\sqrt[]{2}$ – 3
# Come on in vietnam
$rin^{cute}$