Tìm x, biết: $\frac{/x/+1}{3}$ =$\frac{2}{5}$ 2x-1-(5-x)=-10

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1. a)

   `(|x|+1)/3=2/5`

   ⇒`5(|x|+1)=6`

   ⇔`|x|+1=6/5`

   ⇔`|x|=1/5`

   ⇔\(\left[ \begin{array}{l}x=\frac{1}{5}\\x=-\frac{1}{5}\end{array} \right.\)  

   b)

   `2x-1-(5-x)=-10`

   `2x-1-5+x+10=0`

   `3x+4=0`

   `3x=-4`

   `x=-4/3`

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