Tìm x, biết $\frac{3}{2x+1}$ + $\frac{10}{4x+2}$ – $\frac{6}{6x+3}$ = $\frac{12}{26}$

0 bình luận về “Tìm x, biết $\frac{3}{2x+1}$ + $\frac{10}{4x+2}$ – $\frac{6}{6x+3}$ = $\frac{12}{26}$”

1. $\frac{3}{2x+1}$ +$\frac{10}{4x+2}$ -$\frac{6}{6x+3}$ =$\frac{12}{26}$ 

   =>$\frac{3}{2x+1}$ +$\frac{5.2}{2(2x+1)}$ -$\frac{3.2}{3(2x+1)}$ =$\frac{12}{26}$

   =>$\frac{3}{2x+1}$ +$\frac{5}{2x+1}$ -$\frac{2}{2x+1}$ =$\frac{12}{26}$ 

   =>$\frac{6}{2x+1}$ =$\frac{12}{26}$ 

   =>$6.26$=$(2x+1).12$

   =>$156$=$(2x+1).12$

   =>$(2x+1).12$=$156$

   =>$2x+1$=$13$

   =>$2x$=$13-1$

   =>$2x$=$12$

   =>$x$=$6$

    

   Bình luận

2. `\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=12/26`

   `⇔\frac{3}{2x+1}+\frac{10}{2(2x+1)}-\frac{6}{3(2x+1)}=6/13`

   `⇔\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=6/13`

   `⇔\frac{3+5-2}{2x+1}=6/13`

   `⇔\frac{6}{2x+1}=6/13`

   `⇒2x+1=13`

   `⇔2x=12`

   `⇔x=6`

   Bình luận