Tìm x biết : $\frac{x+5}{2\frac{1}{2}}$ = $\frac{40}{x+5}$ ( Ai quê Bỉm Sơn, Thanh Hoá không ạ ) 22/07/2021 Bởi Valentina Tìm x biết : $\frac{x+5}{2\frac{1}{2}}$ = $\frac{40}{x+5}$ ( Ai quê Bỉm Sơn, Thanh Hoá không ạ )
$\dfrac{x+5}{2\dfrac{1}{2}}=\dfrac{40}{x+5}$ $\dfrac{x+5}{\dfrac{5}{2}}=\dfrac{40}{x+5}$ $→(x+5)^2=40.\dfrac{5}{2}=100$ TH1: $x+5=10$ $→x=10-5=5$ TH2: $x+5=-10$ $→x=-10-5=-15$ Vậy $x=5;-10$ Bình luận
`(x+5)/(2,5)=40/(x+5)` `⇒(x+5)^2=40.2,5` `⇒(x+5)^2=100` $⇒\left[ \begin{array}{l}x+5=10\\x+5=-10\end{array} \right.$ $⇒\left[ \begin{array}{l}x=5\\x=-15\end{array} \right.$ (ko) Bình luận
$\dfrac{x+5}{2\dfrac{1}{2}}=\dfrac{40}{x+5}$
$\dfrac{x+5}{\dfrac{5}{2}}=\dfrac{40}{x+5}$
$→(x+5)^2=40.\dfrac{5}{2}=100$
TH1: $x+5=10$
$→x=10-5=5$
TH2: $x+5=-10$
$→x=-10-5=-15$
Vậy $x=5;-10$
`(x+5)/(2,5)=40/(x+5)`
`⇒(x+5)^2=40.2,5`
`⇒(x+5)^2=100`
$⇒\left[ \begin{array}{l}x+5=10\\x+5=-10\end{array} \right.$
$⇒\left[ \begin{array}{l}x=5\\x=-15\end{array} \right.$
(ko)