Tìm các số nguyên x thoả mãn (4x + 3) ⋮ (x – 2). (làm theo 2 cách nha) 23/10/2021 Bởi Claire Tìm các số nguyên x thoả mãn (4x + 3) ⋮ (x – 2). (làm theo 2 cách nha)
@py `C1` `(4x + 3) ⋮ (x – 2)` `⇔4(x-2)+3+8⋮ (x – 2)` `⇔11⋮ (x – 2)` `⇔x-2∈{±1;±11}` `⇔x∈{-9;1;3;13}` `C2` `(4x + 3) ⋮ (x – 2)` `⇔4x+3-4(x-2)⋮ (x – 2)` `⇔4x+3-4x+8⋮ (x – 2)` `⇔11⋮ (x – 2)` `⇔x-2∈{±1;±11}` `⇔x∈{-9;1;3;13}` Bình luận
`4x + 3 ⋮ x – 2` Do `x-2 ⋮ x – 2 => 4x – 8 ⋮ x – 2` `C1: => 4x + 3 – ( 4x – 8) ⋮ x – 2` `=> 4x + 3 – 4x + 8 ⋮ x – 2` `=> 11 ⋮ x – 2` `=> x-2 ∈ Ư(11) = {1;11;-1;-11}` `=> x ∈ {3;13;1;-9}` `C2: => 4x – 8 – (4x + 3 ) ⋮ x – 2` `=> 4x – 8 – 4x – 3 ⋮ x – 2` `=> -11 ⋮ x – 2` `=> x-2 ∈ Ư(-11) = {1;11;-1;-11}` `=> x ∈ {3;13;1;-9}` (Chúc bạn hok tốt ạ) Bình luận
@py
`C1`
`(4x + 3) ⋮ (x – 2)`
`⇔4(x-2)+3+8⋮ (x – 2)`
`⇔11⋮ (x – 2)`
`⇔x-2∈{±1;±11}`
`⇔x∈{-9;1;3;13}`
`C2`
`(4x + 3) ⋮ (x – 2)`
`⇔4x+3-4(x-2)⋮ (x – 2)`
`⇔4x+3-4x+8⋮ (x – 2)`
`⇔11⋮ (x – 2)`
`⇔x-2∈{±1;±11}`
`⇔x∈{-9;1;3;13}`
`4x + 3 ⋮ x – 2`
Do `x-2 ⋮ x – 2 => 4x – 8 ⋮ x – 2`
`C1: => 4x + 3 – ( 4x – 8) ⋮ x – 2`
`=> 4x + 3 – 4x + 8 ⋮ x – 2`
`=> 11 ⋮ x – 2`
`=> x-2 ∈ Ư(11) = {1;11;-1;-11}`
`=> x ∈ {3;13;1;-9}`
`C2: => 4x – 8 – (4x + 3 ) ⋮ x – 2`
`=> 4x – 8 – 4x – 3 ⋮ x – 2`
`=> -11 ⋮ x – 2`
`=> x-2 ∈ Ư(-11) = {1;11;-1;-11}`
`=> x ∈ {3;13;1;-9}`
(Chúc bạn hok tốt ạ)