Tìm các số nguyên x,y,z biết -4/8=x/-10=-7/y=z/-24 09/10/2021 Bởi Arianna Tìm các số nguyên x,y,z biết -4/8=x/-10=-7/y=z/-24
Đáp án: -4/8=-1/2 =>-1/2=x/-10=-7/y=z/24 * -1/2=x/-10 =>2x=10=>x=5 *-1/2=-7/y =>-y=-14=>y=14 -1/2=z/24 =>2z=-24=>z=-12 Vậy x=5;y=14;z=-12 Bình luận
$\begin{array}{l}\dfrac{-4}8=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\Leftrightarrow \dfrac{-1}2=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\text{+ Xét $\dfrac{-1}2=\dfrac x{-10}$}\\\to 2x=-1.(-10)\\\to 2x=10\\\to x=5\\\text{+ Xét $\dfrac{-1}2=\dfrac{-7}y$}\\\to -1y=2.(-7)\\\to -y=-14\\\to y=14\\\text{+ Xét $\dfrac{-1}2=\dfrac z{-24}$}\\\to 2z=(-1).(-24)\\\to 2z=24\\\to z=12\\\text{- Vậy $(x,y,z)=(5,14,12)$} \end{array}$ Bình luận
Đáp án:
-4/8=-1/2
=>-1/2=x/-10=-7/y=z/24
* -1/2=x/-10
=>2x=10=>x=5
*-1/2=-7/y
=>-y=-14=>y=14
-1/2=z/24
=>2z=-24=>z=-12
Vậy x=5;y=14;z=-12
$\begin{array}{l}\dfrac{-4}8=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\Leftrightarrow \dfrac{-1}2=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\text{+ Xét $\dfrac{-1}2=\dfrac x{-10}$}\\\to 2x=-1.(-10)\\\to 2x=10\\\to x=5\\\text{+ Xét $\dfrac{-1}2=\dfrac{-7}y$}\\\to -1y=2.(-7)\\\to -y=-14\\\to y=14\\\text{+ Xét $\dfrac{-1}2=\dfrac z{-24}$}\\\to 2z=(-1).(-24)\\\to 2z=24\\\to z=12\\\text{- Vậy $(x,y,z)=(5,14,12)$} \end{array}$