Toán Tìm đa thức P biết P-($x^{2}$ y-5$y^{2}$ -2)=4$x^{2}$ y+3$y^{2}$ +1 29/07/2021 By Hadley Tìm đa thức P biết P-($x^{2}$ y-5$y^{2}$ -2)=4$x^{2}$ y+3$y^{2}$ +1
`P – (x^2y – 5y^2 -2) = 4x^2y + 3y^2 + 1` `=> P = (4x^2y + 3y^2 + 1) + (x^2y – 5y^2 -2)` `=> P = 4x^2y + 3y^2 + 1 + x^2y – 5y^2 -2` `=> P = (4x^2y + x^2y) + (3y^2 – 5y^2) + (1-2)` `=> P = 5x^2y – 2y^2 – 1` Vậy `P = 5x^2y – 2y^2 – 1` Trả lời
`P-(x²y-5y²-2)=4x²y+3y²+1` `=>P=4x²y+3y²+1+x²y-5y²-2` `=>P=(4x²y+x²y)+(3y²-5y²)+(-2+1)` `=>P=5x²y-2y²-1` Trả lời
`P – (x^2y – 5y^2 -2) = 4x^2y + 3y^2 + 1`
`=> P = (4x^2y + 3y^2 + 1) + (x^2y – 5y^2 -2)`
`=> P = 4x^2y + 3y^2 + 1 + x^2y – 5y^2 -2`
`=> P = (4x^2y + x^2y) + (3y^2 – 5y^2) + (1-2)`
`=> P = 5x^2y – 2y^2 – 1`
Vậy `P = 5x^2y – 2y^2 – 1`
`P-(x²y-5y²-2)=4x²y+3y²+1`
`=>P=4x²y+3y²+1+x²y-5y²-2`
`=>P=(4x²y+x²y)+(3y²-5y²)+(-2+1)`
`=>P=5x²y-2y²-1`