tìm x: $\frac{2}{3}$.x-30%.x=x+ $\frac{7}{15}$ 11/10/2021 Bởi Alaia tìm x: $\frac{2}{3}$.x-30%.x=x+ $\frac{7}{15}$
2/3.-30%.x=x+7/15 x.(2.3-3/100=x+7/15 x.11/30=x+7/15 x.x=7/15-11/30 xm2=1/10 x=1/10 x=√1/10:1/10 x=1/2 Bình luận
$\frac{2}{3}$ . x – 30% . x = x + $\frac{7}{15}$ x . ( $\frac{2}{3}$ – $\frac{3}{10}$ ) = x + $\frac{7}{15}$ x . $\frac{11}{30}$ = x + $\frac{7}{15}$ x . x = $\frac{7}{15}$ – $\frac{11}{30}$ x² = $\frac{1}{10}$ x = √$\frac{1}{10}$ x = $\frac{√10}{10}$ x = $\frac{1}{2}$. Bình luận
2/3.-30%.x=x+7/15
x.(2.3-3/100=x+7/15
x.11/30=x+7/15
x.x=7/15-11/30
xm2=1/10
x=1/10
x=√1/10:1/10
x=1/2
$\frac{2}{3}$ . x – 30% . x = x + $\frac{7}{15}$
x . ( $\frac{2}{3}$ – $\frac{3}{10}$ ) = x + $\frac{7}{15}$
x . $\frac{11}{30}$ = x + $\frac{7}{15}$
x . x = $\frac{7}{15}$ – $\frac{11}{30}$
x² = $\frac{1}{10}$
x = √$\frac{1}{10}$
x = $\frac{√10}{10}$
x = $\frac{1}{2}$.