tìm x |x| – $\frac{3}{4}$ = $\frac{5}{3}$ 23/08/2021 Bởi aikhanh tìm x |x| – $\frac{3}{4}$ = $\frac{5}{3}$
| x | – $\frac{3}{4}$ = $\frac{5}{3}$ ⇒ | x | = $\frac{5}{3}$ + $\frac{3}{4}$ ⇒ | x | = $\frac{20}{12}$ + $\frac{9}{12}$ ⇒ | x | = $\frac{29}{12}$ ⇒ \(\left[ \begin{array}{l}x=\frac{29}{12}\\x=-\frac{29}{12}\end{array} \right.\) Vậy x ∈ { $\frac{29}{12}$ , – $\frac{29}{12}$ } Bình luận
|x| – $\frac{3}{4}$ = $\frac{5}{3}$ |x| = $\frac{5}{3}$ + $\frac{3}{4}$ |x| = $\frac{20}{12}$ + $\frac{9}{12}$ |x| = $\frac{29}{12}$ \(\left[ \begin{array}{l}x=\frac{29}{12}\\x=\frac{-29}{12}\end{array} \right.\) Vậy x = $\frac{29}{12}$ hoặc x = $\frac{-29}{12}$ Bình luận
| x | – $\frac{3}{4}$ = $\frac{5}{3}$
⇒ | x | = $\frac{5}{3}$ + $\frac{3}{4}$
⇒ | x | = $\frac{20}{12}$ + $\frac{9}{12}$
⇒ | x | = $\frac{29}{12}$
⇒ \(\left[ \begin{array}{l}x=\frac{29}{12}\\x=-\frac{29}{12}\end{array} \right.\)
Vậy x ∈ { $\frac{29}{12}$ , – $\frac{29}{12}$ }
|x| – $\frac{3}{4}$ = $\frac{5}{3}$
|x| = $\frac{5}{3}$ + $\frac{3}{4}$
|x| = $\frac{20}{12}$ + $\frac{9}{12}$
|x| = $\frac{29}{12}$
\(\left[ \begin{array}{l}x=\frac{29}{12}\\x=\frac{-29}{12}\end{array} \right.\)
Vậy x = $\frac{29}{12}$ hoặc x = $\frac{-29}{12}$