Tìm x. Giải hộ mình với ạ (x-2).(3-x)=(x-3).(5x+1) 30/08/2021 Bởi Sarah Tìm x. Giải hộ mình với ạ (x-2).(3-x)=(x-3).(5x+1)
Đáp án: `x=3` ;`x=1/6` Giải thích các bước giải: ` (x-2)(3-x) = (x-3).(5x+1)` `<=> (x-2)(3-x) – (x-3)(5x+1) =0` `<=> (x-2)(3-x) + (-1).(x-3)(5x+1)=0` `<=> (x-2)(3-x) + (3-x)(5x+1)=0` `<=> (3-x)(x-2+5x+1)=0` `<=> (3-x)(6x – 1)=0` `<=>` \(\left[ \begin{array}{l}3-x=0\\6x-1=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{6}\end{array} \right.\) Vậy `x=3` hoặc `x=1/6` Bình luận
`(x-2)(3-x)=(x-3)(5x+1)` `<=>(x-2)(3-x)-(x-3)(5x+1)=0` `<=>(x-2)(3-x)+(-1)*(x-3)(5x+1)=0` `<=>(x-2)(3-x)+(3-x)(5x+1)=0` `<=>(3-x)(x-2+5x+1)=0` `<=>(3-x)(6x-1)=0` `<=>`\(\left[ \begin{array}{l}3-x=0\\6x-1=0\end{array} \right.\) `<=>`\(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{6}\end{array} \right.\) `<=>x={3;1/6}` Bình luận
Đáp án: `x=3` ;`x=1/6`
Giải thích các bước giải:
` (x-2)(3-x) = (x-3).(5x+1)`
`<=> (x-2)(3-x) – (x-3)(5x+1) =0`
`<=> (x-2)(3-x) + (-1).(x-3)(5x+1)=0`
`<=> (x-2)(3-x) + (3-x)(5x+1)=0`
`<=> (3-x)(x-2+5x+1)=0`
`<=> (3-x)(6x – 1)=0`
`<=>` \(\left[ \begin{array}{l}3-x=0\\6x-1=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{6}\end{array} \right.\)
Vậy `x=3` hoặc `x=1/6`
`(x-2)(3-x)=(x-3)(5x+1)`
`<=>(x-2)(3-x)-(x-3)(5x+1)=0`
`<=>(x-2)(3-x)+(-1)*(x-3)(5x+1)=0`
`<=>(x-2)(3-x)+(3-x)(5x+1)=0`
`<=>(3-x)(x-2+5x+1)=0`
`<=>(3-x)(6x-1)=0`
`<=>`\(\left[ \begin{array}{l}3-x=0\\6x-1=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{6}\end{array} \right.\)
`<=>x={3;1/6}`