Tìm m để hpt: 2x-y=1 mx+3y=5 có nghiêm âm 07/07/2021 Bởi Kinsley Tìm m để hpt: 2x-y=1 mx+3y=5 có nghiêm âm
Đáp án: Giải thích các bước giải: \(\begin{array}{l}\left\{ \begin{array}{l}y = 2x – 1\\mx + 6x – 3 = 5\end{array} \right. \to \left\{ \begin{array}{l}y = 2x – 1\\x = \frac{8}{{m + 6}}\end{array} \right.\\ \to \left\{ \begin{array}{l}x = \frac{8}{{m + 6}}\\y = \frac{{16 – m – 6}}{{m + 6}} = \frac{{10 – m}}{{m + 6}}\end{array} \right.\\Do:\left\{ \begin{array}{l}x < 0\\y < 0\end{array} \right. \to \left\{ \begin{array}{l}\frac{8}{{m + 6}} < 0\\\frac{{10 – m}}{{m + 6}} < 0\end{array} \right.\\ \to \left\{ \begin{array}{l}m + 6 < 0\\10 – m > 0\\m \ne – 6\end{array} \right. \to \left\{ \begin{array}{l}m < – 6\\m < 10\\m \ne – 6\end{array} \right.\\KL:m < – 6\end{array}\) Bình luận
Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
\left\{ \begin{array}{l}
y = 2x – 1\\
mx + 6x – 3 = 5
\end{array} \right. \to \left\{ \begin{array}{l}
y = 2x – 1\\
x = \frac{8}{{m + 6}}
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = \frac{8}{{m + 6}}\\
y = \frac{{16 – m – 6}}{{m + 6}} = \frac{{10 – m}}{{m + 6}}
\end{array} \right.\\
Do:\left\{ \begin{array}{l}
x < 0\\
y < 0
\end{array} \right. \to \left\{ \begin{array}{l}
\frac{8}{{m + 6}} < 0\\
\frac{{10 – m}}{{m + 6}} < 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
m + 6 < 0\\
10 – m > 0\\
m \ne – 6
\end{array} \right. \to \left\{ \begin{array}{l}
m < – 6\\
m < 10\\
m \ne – 6
\end{array} \right.\\
KL:m < – 6
\end{array}\)