Tìm x sao cho (1/2 + 1/4 + 1/8 + 1/16) : x = 1/2 + 1/6 + 1/12 +1/20 + … + 1/132 18/07/2021 Bởi aikhanh Tìm x sao cho (1/2 + 1/4 + 1/8 + 1/16) : x = 1/2 + 1/6 + 1/12 +1/20 + … + 1/132
Đáp án: `x=45/44` Giải thích các bước giải: `(1/2 + 1/4 + 1/8 + 1/16) : x = 1/2 + 1/6 + 1/12 +1/20 + … + 1/132` `=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1/1.2 + 1/2.3 + 1/3.4 +1/4.5 + … + 1/11.12` `=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+…+1/11-1/12` `=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-(1/2-1/2+1/3-1/3+1/4-1/4+1/5-…-1/11+1/12)` `=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-1/12` `=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 11/12` `=>` `x=(1/2+1/4+1/8+1/16) : 11/12` `=>` `x=11/12×(8/16+4/16+2/16+1/16) : 11/12` `=>` `x=15/16 : 11/12` `=>` `x=45/44` Bình luận
Xét: A = 1/2 + 1/4 + 1/8 + 1/16 2A = 1 + 1/2 + 1/4 + 1/8 2A – A = 1 – 1/16 => A = 15/16 Xét: B=1/2 + 1/6 + 1/12 +…+ 1/132B=1/1.2 +1/2.3 +1/3.4 +… +1/11.12B=1 – 1/1 +1/2 -1/3 +1/3 -1/4 +… +1/11 -1/12B=1 – 1/12=>B=11/12Thay vào ta có15/16 : x =11/12=>x =15/16 : 11/12=>x = 45/44 Bình luận
Đáp án:
`x=45/44`
Giải thích các bước giải:
`(1/2 + 1/4 + 1/8 + 1/16) : x = 1/2 + 1/6 + 1/12 +1/20 + … + 1/132`
`=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1/1.2 + 1/2.3 + 1/3.4 +1/4.5 + … + 1/11.12`
`=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+…+1/11-1/12`
`=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-(1/2-1/2+1/3-1/3+1/4-1/4+1/5-…-1/11+1/12)`
`=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 1-1/12`
`=>` `(1/2 + 1/4 + 1/8 + 1/16) : x = 11/12`
`=>` `x=(1/2+1/4+1/8+1/16) : 11/12`
`=>` `x=11/12×(8/16+4/16+2/16+1/16) : 11/12`
`=>` `x=15/16 : 11/12`
`=>` `x=45/44`
Xét:
A = 1/2 + 1/4 + 1/8 + 1/16
2A = 1 + 1/2 + 1/4 + 1/8
2A – A = 1 – 1/16
=> A = 15/16
Xét:
B=1/2 + 1/6 + 1/12 +…+ 1/132
B=1/1.2 +1/2.3 +1/3.4 +… +1/11.12
B=1 – 1/1 +1/2 -1/3 +1/3 -1/4 +… +1/11 -1/12
B=1 – 1/12
=>B=11/12
Thay vào ta có
15/16 : x =11/12
=>x =15/16 : 11/12
=>x = 45/44