tìm số nguyên x a) l48-3xl =0 b) l -x -7l= 24 c)l4-xl=21 d) lx+8l+12=0 06/08/2021 Bởi Josie tìm số nguyên x a) l48-3xl =0 b) l -x -7l= 24 c)l4-xl=21 d) lx+8l+12=0
a, l48-3xl =0 ⇒48-3x=0 ⇒3x=48 ⇒x=16 b, |-x-7|=24 ⇒\(\left[ \begin{array}{l}-x-7=24\\-x-7=-24\end{array} \right.\)⇒\(\left[ \begin{array}{l}x=-31\\x=17\end{array} \right.\) Vậy x=-31; x=17 c)l4-xl=21 ⇒\(\left[ \begin{array}{l}4-x=21\\4-x=-21\end{array} \right.\)⇒\(\left[ \begin{array}{l}x=-17\\x=25\end{array} \right.\) Vậy x=-17, x=25 (Học tốt nhé!) Bình luận
a) l48-3xl=0 48-3x = 0 3x= 48-0 3x= 48 x=48:3 x= 16 b) l -x -7l= 24 x-7= 24 x= 24+7 x=31 c)l4-xl=21 TH1 ; 4-x=21 x= 4-21 x= -17 TH2 : 4-x = -21 x=4-(-21) x=25 vậy x = -17 hoặc x=25 d) lx+8l+12=0 lx+8l = 0-12 lx+8l = -12 TH1 : x+ 8 = 12 x= 12-8 x= 4 TH2: x+8 = -12 x= (-12) – 8 x= -20 vậy x= 4 hoặc x=-20 Bình luận
a, l48-3xl =0
⇒48-3x=0
⇒3x=48
⇒x=16
b, |-x-7|=24
⇒\(\left[ \begin{array}{l}-x-7=24\\-x-7=-24\end{array} \right.\)⇒\(\left[ \begin{array}{l}x=-31\\x=17\end{array} \right.\)
Vậy x=-31; x=17
c)l4-xl=21
⇒\(\left[ \begin{array}{l}4-x=21\\4-x=-21\end{array} \right.\)⇒\(\left[ \begin{array}{l}x=-17\\x=25\end{array} \right.\)
Vậy x=-17, x=25
(Học tốt nhé!)
a) l48-3xl=0
48-3x = 0
3x= 48-0
3x= 48
x=48:3
x= 16
b) l -x -7l= 24
x-7= 24
x= 24+7
x=31
c)l4-xl=21
TH1 ; 4-x=21
x= 4-21
x= -17
TH2 : 4-x = -21
x=4-(-21)
x=25
vậy x = -17 hoặc x=25
d) lx+8l+12=0
lx+8l = 0-12
lx+8l = -12
TH1 : x+ 8 = 12
x= 12-8
x= 4
TH2: x+8 = -12
x= (-12) – 8
x= -20
vậy x= 4 hoặc x=-20