Tìm số nguyên x , biết : 1) (5-x)(8-x) < 0 2) 1<|x|<3 3) |-x| = 3,6 24/07/2021 Bởi Ariana Tìm số nguyên x , biết : 1) (5-x)(8-x) < 0 2) 1<|x|<3 3) |-x| = 3,6
Giải thích các bước giải: Ta có: \(\begin{array}{l}1,\\\left( {5 – x} \right)\left( {8 – x} \right) < 0\\ \Leftrightarrow \left[ \begin{array}{l}\left\{ \begin{array}{l}5 – x > 0\\8 – x < 0\end{array} \right.\\\left\{ \begin{array}{l}5 – x < 0\\8 – x > 0\end{array} \right.\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}\left\{ \begin{array}{l}x < 5\\x > 8\end{array} \right.\\\left\{ \begin{array}{l}x > 5\\x < 8\end{array} \right.\end{array} \right. \Leftrightarrow 5 < x < 8\\2,\\1 < \left| x \right| < 3\\ \Leftrightarrow \left\{ \begin{array}{l}\left| x \right| > 1\\\left| x \right| < 3\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}\left[ \begin{array}{l}x > 1\\x < – 1\end{array} \right.\\ – 3 < x < 3\end{array} \right. \Leftrightarrow \left[ \begin{array}{l} – 3 < x < – 1\\1 < x < 3\end{array} \right.\\3,\\\left| { – x} \right| = 3,6\\ \Leftrightarrow \left[ \begin{array}{l} – x = 3,6\\ – x = – 3,6\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}x = – 3,6\\x = 3,6\end{array} \right.\end{array}\) Bình luận
Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
1,\\
\left( {5 – x} \right)\left( {8 – x} \right) < 0\\
\Leftrightarrow \left[ \begin{array}{l}
\left\{ \begin{array}{l}
5 – x > 0\\
8 – x < 0
\end{array} \right.\\
\left\{ \begin{array}{l}
5 – x < 0\\
8 – x > 0
\end{array} \right.
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
\left\{ \begin{array}{l}
x < 5\\
x > 8
\end{array} \right.\\
\left\{ \begin{array}{l}
x > 5\\
x < 8
\end{array} \right.
\end{array} \right. \Leftrightarrow 5 < x < 8\\
2,\\
1 < \left| x \right| < 3\\
\Leftrightarrow \left\{ \begin{array}{l}
\left| x \right| > 1\\
\left| x \right| < 3
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
\left[ \begin{array}{l}
x > 1\\
x < – 1
\end{array} \right.\\
– 3 < x < 3
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
– 3 < x < – 1\\
1 < x < 3
\end{array} \right.\\
3,\\
\left| { – x} \right| = 3,6\\
\Leftrightarrow \left[ \begin{array}{l}
– x = 3,6\\
– x = – 3,6
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = – 3,6\\
x = 3,6
\end{array} \right.
\end{array}\)