tìm số nguyên x, biết: a) |x-2|=3 b) |x+2|=3 c) |x+2|=x+2 d) |x-2|=2-x e) |x-1|=3 g) |x-12|=-1 28/11/2021 Bởi Nevaeh tìm số nguyên x, biết: a) |x-2|=3 b) |x+2|=3 c) |x+2|=x+2 d) |x-2|=2-x e) |x-1|=3 g) |x-12|=-1
a, |x-2| = 3 * TH1: x-2 = 3 (x>2) x = 5 *TH2: x-2 = -3 x= -1 b) |x+2|=3 *TH1: (x> -2) x+2 = 3 x = 1 *TH2: (x< -2) x+2 = -3 x = -5 c) |x+2|=x+2 *TH1: (x>-2) x+2 = -(x+2) x+2 = -x-2 2x = -4 x = -2 d) |x-2|=2-x *TH1: (x>2) x-2 = 2-x 2x = 4 x = 2 *TH2: (x<2) x-2 = -(2-x) x-2 = -2 +x 0x =0 x = 0 e) |x-1|=3 *TH1: (x>1) x-1 = 3 x = 4 *TH2: (x<1) x-1 = -3 x = -2 g) |x-12|=-1 *TH1: (x>12) x-12 = -1 x = 11 *TH2: (x<12) x-12 = 1 x = 13 Bình luận
|x-2|=3 x-2=3 x=3+2 x=5 b)|x+2|=3 x+2=3 x=3-2 x=1 c)|x+2|=x+2 x+2=x+2 d) |x-2|=2-x x-2=2-x x=0 e) |x-1|=3 x-1=3 x=3+1 x=4 g) |x_12|=1 x-12=1 x=1+12 x=13 Bình luận
a, |x-2| = 3
* TH1:
x-2 = 3 (x>2)
x = 5
*TH2:
x-2 = -3
x= -1
b) |x+2|=3
*TH1: (x> -2)
x+2 = 3
x = 1
*TH2: (x< -2)
x+2 = -3
x = -5
c) |x+2|=x+2
*TH1: (x>-2)
x+2 = -(x+2)
x+2 = -x-2
2x = -4
x = -2
d) |x-2|=2-x
*TH1: (x>2)
x-2 = 2-x
2x = 4
x = 2
*TH2: (x<2)
x-2 = -(2-x)
x-2 = -2 +x
0x =0
x = 0
e) |x-1|=3
*TH1: (x>1)
x-1 = 3
x = 4
*TH2: (x<1)
x-1 = -3
x = -2
g) |x-12|=-1
*TH1: (x>12)
x-12 = -1
x = 11
*TH2: (x<12)
x-12 = 1
x = 13
|x-2|=3
x-2=3
x=3+2
x=5
b)|x+2|=3
x+2=3
x=3-2
x=1
c)|x+2|=x+2
x+2=x+2
d) |x-2|=2-x
x-2=2-x
x=0
e) |x-1|=3
x-1=3
x=3+1
x=4
g) |x_12|=1
x-12=1
x=1+12
x=13