Tìm sô Nguyên X thoa mãn a, 5-/x/-1 b, 10+/x-1/=14 c, 42-/x/=13 d, 2/x+3/-5=13 e, 15-3/x-4/=(5)-(-2) 17/11/2021 Bởi Camila Tìm sô Nguyên X thoa mãn a, 5-/x/-1 b, 10+/x-1/=14 c, 42-/x/=13 d, 2/x+3/-5=13 e, 15-3/x-4/=(5)-(-2)
$a$ $ko$ $rõ$ $đề$ b)10+|x-1|=14 |x-1|=14-10 |x-1|=4 x=4+1 x=5 c)42-|x|=13 |x|=42-13 |x|=29 d)2|x+3|-5=13 2|x+3|=13+5 2|x+3|=18 |x+3|=18:2 |x+3|=9 x=9-3 x=6 (+5) hay (-5) ???? mk thay (-5) nhé e) 15-3|x-4|=(-5)-(-2) 15-3|x-4|=(-5)+2 15-3|x-4|=-3 3|x-4|=15-(-3) 3|x-4|=15+3 3|x-4|=18 |x-4|=18:3 |x-4|=6 x=6-4 x=2 Bình luận
A) KO RÕ ĐỀ B)10+|x-1|=14 |x-1|=14-10 x-1=4 x=4+1 x=5 C)42-|x|=13 |x|=42-13 |x|=29 D)2|x+3|-5=13 2|x+3|=13+5 2|x+3|=17 |x+3|=8.5 x+3=8.5 x=5.5 Bình luận
$a$ $ko$ $rõ$ $đề$
b)10+|x-1|=14
|x-1|=14-10
|x-1|=4
x=4+1
x=5
c)42-|x|=13
|x|=42-13
|x|=29
d)2|x+3|-5=13
2|x+3|=13+5
2|x+3|=18
|x+3|=18:2
|x+3|=9
x=9-3
x=6
(+5) hay (-5) ????
mk thay (-5) nhé
e) 15-3|x-4|=(-5)-(-2)
15-3|x-4|=(-5)+2
15-3|x-4|=-3
3|x-4|=15-(-3)
3|x-4|=15+3
3|x-4|=18
|x-4|=18:3
|x-4|=6
x=6-4
x=2
A) KO RÕ ĐỀ
B)10+|x-1|=14
|x-1|=14-10
x-1=4
x=4+1
x=5
C)42-|x|=13
|x|=42-13
|x|=29
D)2|x+3|-5=13
2|x+3|=13+5
2|x+3|=17
|x+3|=8.5
x+3=8.5
x=5.5