Tìm sô Nguyên X thoa mãn a, 5-/x/-1 b, 10+/x-1/=14 c, 42-/x/=13 d, 2/x+3/-5=13 e, 15-3/x-4/=(5)-(-2)

$a$ $ko$ $rõ$ $đề$

b)10+|x-1|=14

|x-1|=14-10

|x-1|=4

x=4+1

x=5

c)42-|x|=13

|x|=42-13

|x|=29

d)2|x+3|-5=13

2|x+3|=13+5

2|x+3|=18

|x+3|=18:2

|x+3|=9

x=9-3

x=6

(+5) hay (-5) ????

mk thay (-5) nhé

e) 15-3|x-4|=(-5)-(-2)

15-3|x-4|=(-5)+2

15-3|x-4|=-3

3|x-4|=15-(-3)

3|x-4|=15+3

3|x-4|=18

|x-4|=18:3

|x-4|=6

x=6-4

x=2