2021 Bởi Adalyn

tìm x thuôc z
5/17+-4/19+-20/21+12/17+-11/31 { "@context": "https://schema.org", "@type": "QAPage", "mainEntity": { "@type": "Question", "name": " tìm x thuôc z 5/17+-4/19+-20/21+12/17+-11/31

0 bình luận về “tìm x thuôc z 5/17+-4/19+-20/21+12/17+-11/31<x/9< hoặc bằng -3/7+7/15+4/-7+8/15+2/3”

hoaianh

26/10/2021 vào lúc 08:41

5/17+-4/19+-20/21+12/17+-11/31<x/9< hoặc bằng -3/7+7/15+4/-7+8/15+2/3

$\to (\frac{5}{17} + \frac{12}{17}) + \frac{- 4}{19} + \frac{- 20}{21} + \frac{- 11}{31} < \frac{x}{9} \leq (\frac{- 3}{7} + \frac{4}{- 7}) + (\frac{7}{15} + \frac{8}{15}) + \frac{2}{3}$

$\to 1 + \frac{- 4}{19} + \frac{- 20}{21} + \frac{- 11}{31} < \frac{x}{9} \leq (\frac{- 3}{7} - \frac{4}{7}) + 1 + \frac{2}{3}$

$\to \frac{12369}{12369} - \frac{2604}{12369} - \frac{11780}{12369} - \frac{4389}{12369} < \frac{x}{9} \leq - 1 + 1 + \frac{2}{3}$

$\to - \frac{19212}{4123} < x \leq 6$

$\to - \frac{19212}{4123} < x \leq 6$

$\to - 4 \leq x \leq 6$ vì $x \in Z$

$\to x \in {- 4, - 3, - 2, - 1, 0, 1, 2, 3, 4, 5, 6}$

$\to x \in {- 4, - 3, - 2, - 1, 0, 1, 2, 3, 4, 5, 6}$
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