tìm x trong các tỉ lê thức sau a)3: 2$\frac{1}{4}$ =$\frac{3}{4}$:(6.x)

a, $3:2\dfrac{1}{4}=\dfrac{3}{4}:(6.x)$
$\dfrac{4}{3}=\dfrac{3}{4}:(6.x)$

$\dfrac{3}{4}:\dfrac{4}{3}=6.x$
$\dfrac{9}{16}=6.x$
$\dfrac{9}{16}:6=x$
$\dfrac{3}{32}=x$
Vậy $x=\dfrac{3}{32}$