Tìm x trong tỉ lệ thực a x/2,7=0,7/6,3 b 5,4/13,5=2,4/x c -15:35=27:x 12/07/2021 Bởi Alice Tìm x trong tỉ lệ thực a x/2,7=0,7/6,3 b 5,4/13,5=2,4/x c -15:35=27:x
`\text{a)}` `x/{2,7} = {0,7}/{6,3}` `-> x = {0,7}/{6,3} . 2,7` `-> x = 0,3` Vậy `x = 0,3` `\text{b)}` `{5,4}/{13,6} = {2,4}/x` `-> 27/68 = {2,4}/x` `-> x = 2,4 . 68/27` `-> x = 272/45` Vậy `x = 272/45` `\text{c)}` `-15 : 35 = 27 : x` `-> {-15}/35 = 27:x` `-> x = 27 : {-15}/35` `-> x = 27 . {35}/{-15}` `-> x = -63` Vậy `x = -63` Bình luận
`a)` `frac\{x}{2,7}=frac\{0,7}{6,3}` `=>x=frac\{0,7}{6,3].2,7` `=>x=0,3` `b)` `frac\{5,4}{13,5}=frac\{2,4}{x}` `=>frac\{27}{68}=frac\{2,4}{x}` `=>x=2,4. 68/27` `=>x=272/45` `c)` `-15:35=27:x` `=>-15/35=27/x` `=>x=27: -15/35` `=>x=-63` Bình luận
`\text{a)}`
`x/{2,7} = {0,7}/{6,3}`
`-> x = {0,7}/{6,3} . 2,7`
`-> x = 0,3`
Vậy `x = 0,3`
`\text{b)}`
`{5,4}/{13,6} = {2,4}/x`
`-> 27/68 = {2,4}/x`
`-> x = 2,4 . 68/27`
`-> x = 272/45`
Vậy `x = 272/45`
`\text{c)}`
`-15 : 35 = 27 : x`
`-> {-15}/35 = 27:x`
`-> x = 27 : {-15}/35`
`-> x = 27 . {35}/{-15}`
`-> x = -63`
Vậy `x = -63`
`a)`
`frac\{x}{2,7}=frac\{0,7}{6,3}`
`=>x=frac\{0,7}{6,3].2,7`
`=>x=0,3`
`b)`
`frac\{5,4}{13,5}=frac\{2,4}{x}`
`=>frac\{27}{68}=frac\{2,4}{x}`
`=>x=2,4. 68/27`
`=>x=272/45`
`c)`
`-15:35=27:x`
`=>-15/35=27/x`
`=>x=27: -15/35`
`=>x=-63`