tìm y biết (20/112+20/280+20/520+….+20/5920) y =8/3

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1. ` (20/112+20/280+20/520+…+20/5920). y =8/3`

   `(20/8.14+20/14.20+20/20.26+…+20/74.80).y=8/3`

   `10/3(6/8.14+6/14.20+6/20.26+…+6/74.80).y=8/3`

   `10/3(1/8-1/14+1/14-1/20+1/20-1/26+…+1/74-1/80).y=8/3`

   `10/3(1/8-1/80).y=8/3`

   `10/3*9/80.y=8/3`

   `3/8.y=8/3`

   `y=8/3:3/8`

   `y=64/9`

   Vậy `y=64/9`.

    

   Trả lời

2. Đáp án + Giải thích các bước giải:

   `(20/112+20/280+20/520+….+20/5920). y =8/3`

   `to 20. (1/112 + 1/280+..+1/5920).y=8/3`

   `to 10/3 . (6/(8.14)+6/(14.20)+…+6/(74.80)).y=8/3`

   `to 10/3 . (1/8-1/14+1/14-1/20+…+1/74-1/80).y=8/3`

   `to 10/3 . (1/8-1/80).y=8/3`

   `to 10/3 . 9/80 .y=8/3`

   `to 3/8 . y = 8/3`

   `to y=8/3 : 3/8=64/9`

   Vậy `y=64/9`

   Trả lời