Tìm x,y thuộc Z biết :
a) ( x + 1 )( y – 2) = 0
b) ( x – 5 )( y – 7 ) = 1
c) (x + 4 )( y – 2 ) = 2
d) ( x + 3 )( y – 6 ) = -4
e) ( x + 7 )( 5 – y ) = -6
f) ( 12 – x )( 6 – y ) = -2
HELP ME NHÓOOOO !!! Thanks nhìu lém 😀
Tìm x,y thuộc Z biết :
a) ( x + 1 )( y – 2) = 0
b) ( x – 5 )( y – 7 ) = 1
c) (x + 4 )( y – 2 ) = 2
d) ( x + 3 )( y – 6 ) = -4
e) ( x + 7 )( 5 – y ) = -6
f) ( 12 – x )( 6 – y ) = -2
HELP ME NHÓOOOO !!! Thanks nhìu lém 😀
Đáp án:
Giải thích các bước giải:
a,
⇒\(\left[ \begin{array}{l}x+1=0\\y-2=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=-1\\y=2\end{array} \right.\)
b,
⇒\(\left[ \begin{array}{l}x-5=1\\y-7=1\end{array} \right.\)
\(\left[ \begin{array}{l}x-5=-1\\y-7=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=6\\y=8\end{array} \right.\)
\(\left[ \begin{array}{l}x=4\\y=-8\end{array} \right.\)
c,
⇒\(\left[ \begin{array}{l}x+4=2\\y-2=1\end{array} \right.\)
\(\left[ \begin{array}{l}x+4=-2\\y-2=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=-2\\y=3\end{array} \right.\)
\(\left[ \begin{array}{l}x=-6\\y=1\end{array} \right.\)
f,
⇒\(\left[ \begin{array}{l}12-x=2\\6-y=-1\end{array} \right.\)
\(\left[ \begin{array}{l}12-x=-2\\6-y=1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=10\\y=7\end{array} \right.\)
\(\left[ \begin{array}{l}x=14\\y=5\end{array} \right.\)