Tìm y y+y+ $\frac{7}{8}$ + y× $\frac{9}{2}$=255

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1. y + y + `7/8` + y × `9/2` = 255

   2y + `7/8` + y × `9/2` = 255

   y × ( 2 + `9/2` ) + `7/8` = 255

   y × ( `4/2` + `9/2` ) + `7/8` = 255

   y × `13/2` + `7/8` = 255

   y × `13/2` = 255 – `7/8`

   y × `13/2` = `2040/8` – `7/8`

   y × `13/2` = `2033/8`

   y = `2033/8` ÷ `13/2`

   y = `2033/8` × `2/13`

   y = `2033/52`

   @peachybee

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2. `y+y+7/8 +y×9/2=255`

   `2×y+7/8+y×9/2=255`

   `y×(2+ 9/2)+7/8=255`

   `y×13/2 +7/8=255`

   `y×13/2=255- 7/8`

   `y×13/2=2040/8 -7/8`

   `y×13/2=2033/8`

   `y=2033/8: 13/2`

   `y=2033/52`

   chúc học tốt

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