Tìm x€Z a)x-14=3x+18 b)2(x-5)-3(x-4)=-6+15(-3) c)(x+7)(x-9)=0 d)|2x-5|-7=22

a)x-14=3x+18

⇔x-3x=18+14

⇔-2x=32

⇔    x=-16

Vậy x=-16

b)2(x-5)-3(x-4)=-6+15(-3)

⇔2x-10-3x+12=-6-45

⇔2x-3x=-6-45+10-12

⇔-x=-53

⇔x=53

Vậy x=53

c)(x+7)(x-9)=0

⇔\(\left[ \begin{array}{l}x+7=0\\x-9=0\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=0-7\\x=0+9\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-7\\x=9\end{array} \right.\) 

Vậy x=-7; x=9

d)|2x-5|=22+7

⇔|2x-5|=29

⇔\(\left[ \begin{array}{l}2x-5=29\\2x-5=-29\end{array} \right.\)⇔\(\left[ \begin{array}{l}2x=29+5\\2x=-29+5\end{array} \right.\)⇔\(\left[ \begin{array}{l}2x=34\\2x=-24\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=34:2\\x=-24:2\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=17\\x=-12\end{array} \right.\) 

Vậy x=17; x=12.