TÍNH 1+1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66 25/08/2021 Bởi Ayla TÍNH 1+1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66
Đáp án: 11/6 Giải thích các bước giải: 1+1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66 =2/2+2/6+2/12+2/20+……….+2/90+2/110+2/132 =2x(1/1×2+1/2×3+1/3×4+1/4×5+……..+1/10×11+1/11×12) =2x(1-1/2+1/2-1/3+1/3-1/4+…………+1/10-1/11+1/11-1/12) =2x(1-1/12) =2×11/12 =11/6 Bình luận
Đáp án: \(\frac{11}{6}\) Giải thích các bước giải: \[\begin{array}{l}1 + \frac{1}{3} + \frac{1}{6} + \frac{1}{{10}} + \frac{1}{{15}} + \frac{1}{{21}} + \frac{1}{{28}} + \frac{1}{{36}} + \frac{1}{{45}} + \frac{1}{{55}} + \frac{1}{{66}}\\ = \frac{2}{2} + \frac{2}{6} + \frac{2}{{12}} + \frac{2}{{20}} + \frac{2}{{30}} + …+ \frac{2}{{90}} + \frac{2}{{110}} + \frac{2}{{132}}\\ = 2 \times \left( {\frac{1}{{1 \times 2}} + \frac{1}{{2 \times 3}} + \frac{1}{{3 \times 4}} + \frac{1}{{4 \times 5}} + \frac{1}{{5 \times 6}} + …+ \frac{1}{{9 \times 10}} + \frac{1}{{10 \times 11}} + \frac{1}{{11 \times 12}}} \right)\\ = 2 \times \left( {1 – \frac{1}{2} + \frac{1}{2} – \frac{1}{3} + \frac{1}{3} – \frac{1}{4} + \frac{1}{4} – \frac{1}{5} +… + \frac{1}{{10}} – \frac{1}{{11}} + \frac{1}{{11}} – \frac{1}{{12}}} \right)\\ = 2 \times \left( {1 – \frac{1}{{12}}} \right)\\ = 2 \times \frac{{11}}{{12}}\\ = \frac{{11}}{6}\end{array}\] Bình luận
Đáp án:
11/6
Giải thích các bước giải:
1+1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66
=2/2+2/6+2/12+2/20+……….+2/90+2/110+2/132
=2x(1/1×2+1/2×3+1/3×4+1/4×5+……..+1/10×11+1/11×12)
=2x(1-1/2+1/2-1/3+1/3-1/4+…………+1/10-1/11+1/11-1/12)
=2x(1-1/12)
=2×11/12
=11/6
Đáp án:
\(\frac{11}{6}\)
Giải thích các bước giải:
\[\begin{array}{l}
1 + \frac{1}{3} + \frac{1}{6} + \frac{1}{{10}} + \frac{1}{{15}} + \frac{1}{{21}} + \frac{1}{{28}} + \frac{1}{{36}} + \frac{1}{{45}} + \frac{1}{{55}} + \frac{1}{{66}}\\
= \frac{2}{2} + \frac{2}{6} + \frac{2}{{12}} + \frac{2}{{20}} + \frac{2}{{30}} + …+ \frac{2}{{90}} + \frac{2}{{110}} + \frac{2}{{132}}\\
= 2 \times \left( {\frac{1}{{1 \times 2}} + \frac{1}{{2 \times 3}} + \frac{1}{{3 \times 4}} + \frac{1}{{4 \times 5}} + \frac{1}{{5 \times 6}} + …+ \frac{1}{{9 \times 10}} + \frac{1}{{10 \times 11}} + \frac{1}{{11 \times 12}}} \right)\\
= 2 \times \left( {1 – \frac{1}{2} + \frac{1}{2} – \frac{1}{3} + \frac{1}{3} – \frac{1}{4} + \frac{1}{4} – \frac{1}{5} +… + \frac{1}{{10}} – \frac{1}{{11}} + \frac{1}{{11}} – \frac{1}{{12}}} \right)\\
= 2 \times \left( {1 – \frac{1}{{12}}} \right)\\
= 2 \times \frac{{11}}{{12}}\\
= \frac{{11}}{6}
\end{array}\]