Tính (2x+3)(x+2) B, (3xy²+6x²y-9xy):3xy C, (x+2)²/x-1* x+2/x-1 23/11/2021 Bởi Gabriella Tính (2x+3)(x+2) B, (3xy²+6x²y-9xy):3xy C, (x+2)²/x-1* x+2/x-1
Đáp án: ` a)` `(2x+3)(x+2) = 2x^2 +4x +3x +6 = 2x^2 +7x +6` `b)` ` (3xy^2 +6x^2y -9xy) : 3xy` ` = 3xy(y + 2x – 3) : 3xy` ` = 2x + y -3` `c)` ` ((x+2)^2)/(x-1) * (x+2)/(x-1)` ` = ((x+2)^3)/(x-1)^2` Bình luận
`~rai~` $\begin{array}{I}a.(2x+3)(x+2)\\=2x^2+4x+3x+6\\=2x^2+7x+6.\\b.(3xy^2+6x^2y-9xy):3xy\\=y+2x-3.\\c.\dfrac{(x+2)^2}{x-1}.\dfrac{x+2}{x-1}\\=\dfrac{(x-2)^3}{(x-1)^2}.\end{array}$ Bình luận
Đáp án:
` a)`
`(2x+3)(x+2) = 2x^2 +4x +3x +6 = 2x^2 +7x +6`
`b)`
` (3xy^2 +6x^2y -9xy) : 3xy`
` = 3xy(y + 2x – 3) : 3xy`
` = 2x + y -3`
`c)`
` ((x+2)^2)/(x-1) * (x+2)/(x-1)`
` = ((x+2)^3)/(x-1)^2`
`~rai~`
$\begin{array}{I}a.(2x+3)(x+2)\\=2x^2+4x+3x+6\\=2x^2+7x+6.\\b.(3xy^2+6x^2y-9xy):3xy\\=y+2x-3.\\c.\dfrac{(x+2)^2}{x-1}.\dfrac{x+2}{x-1}\\=\dfrac{(x-2)^3}{(x-1)^2}.\end{array}$