Tính (2x+3)(x+2) B, (3xy²+6x²y-9xy):3xy C, (x+2)²/x-1* x+2/x-1

Tính (2x+3)(x+2)
B, (3xy²+6x²y-9xy):3xy
C, (x+2)²/x-1* x+2/x-1

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  1. Đáp án:

     

    ` a)`

    `(2x+3)(x+2) = 2x^2 +4x +3x +6 = 2x^2 +7x +6`

    `b)`

    ` (3xy^2 +6x^2y  -9xy) : 3xy`

    ` = 3xy(y + 2x – 3) : 3xy`

    ` = 2x + y -3`

    `c)`

    ` ((x+2)^2)/(x-1) * (x+2)/(x-1)`

    ` = ((x+2)^3)/(x-1)^2`

     

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  2. `~rai~`

    $\begin{array}{I}a.(2x+3)(x+2)\\=2x^2+4x+3x+6\\=2x^2+7x+6.\\b.(3xy^2+6x^2y-9xy):3xy\\=y+2x-3.\\c.\dfrac{(x+2)^2}{x-1}.\dfrac{x+2}{x-1}\\=\dfrac{(x-2)^3}{(x-1)^2}.\end{array}$

     

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