TÍNH ; (2+5)-(-1-4) ; +6-(-1+30) ; +8-(-3+1) ; 10+(4-1) ; (3+1)-(2-1) “ TÌM X : (2X-1) .(2X)=0 ; (3X-6).X=0 ; 2X.(3X+1)=0 ; (5X-1).(2X+1)=0 ; (8X+3).(X+1)=0
TÍNH ; (2+5)-(-1-4) ; +6-(-1+30) ; +8-(-3+1) ; 10+(4-1) ; (3+1)-(2-1) “ TÌM X : (2X-1) .(2X)=0 ; (3X-6).X=0 ; 2X.(3X+1)=0 ; (5X-1).(2X+1)=0 ; (8X+3).(X+1)=0
Giải thích các bước giải:
Tính
`(2+5)-(-1-4)`
`=7+5`
`=12`
`+6-(-1+30)`
`=6+1-30`
`=7-30`
`=-23`
`+8-(-3+1)`
`=8+3-1`
`=11-1`
`=10`
`10+(4-1) `
`=10+3`
`=13`
`(3+1)-(2-1)`
`=4-1`
`=3`
Tìm `x`
`(2x-1).(2x)=0`
`=>`\(\left[ \begin{array}{l}2x-1=0\\2x=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=1\\x=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=0\end{array}\right .\)
` (3x-6).x=0`
`=>`\(\left[ \begin{array}{l}3x-6=0\\x=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}3x=6\\x=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=2\\x=0\end{array} \right.\)
`2x.(3x+1)=0`
`=>`\(\left[ \begin{array}{l}2x=0\\3x+1=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\3x=-1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x=\dfrac{-1}{3}\end{array} \right.\)
` (5x-1).(2x+1)=0`
`=>`\(\left[ \begin{array}{l}5x-1=0\\x=2x+1=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}5x=1\\2x=-1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{5}\\x=\dfrac{-1}{2}\end{array} \right.\)
`(8x+3).(x+1)=0`
`=>`\(\left[ \begin{array}{l}8x+3=0\\x+1=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}8x=-3\\x=-1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{-3}{8}\\x=-1\end{array} \right.\)
Đáp án:
Bài 1:
(2+5)-(-1-4)
= 7 – (-5)
= 7 + 5
= 12
6 – (-1+30)
= 6 – 29
= – 23
8 – (-3+1)
= 8 – (-2)
= 8 + 2
= 10
10 + (4-1)
= 10 + 3
= 13
(3+1)-(2-1)
= 4 – 1
= 3
Bài 2:
(2x – 1). 2x = 0
<=> 2x-1=0 <=> 2x=1 <=> 2x=1
hoặc 2x=0 <=> x =0
(3X-6).X=0
<=> 3x-6=0 <=> 3x=6 <=> x=2
hoặc x=0
2X.(3X+1)=0
<=> 2x=0 <=> x=0
hoặc 3x+1=0 <=> 3x=-1 <=> x=-1/3
(5X-1).(2X+1)=0
<=> 5x-1=0 <=> 5x=1 <=> x=1/5
hoặc 2x+1=0 <=> 2x=-1 <=>x=-1/2
(8X+3).(X+1)=0
<=> 8x+3=0 <=> 8x=-3 <=> x=-3/8
hoặc x+1=0 <=> x=-1
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