tính 3x+2/x^2-2x+1 -6/x^2-1 -3x-2/x^2+2x+1 16/08/2021 Bởi Josephine tính 3x+2/x^2-2x+1 -6/x^2-1 -3x-2/x^2+2x+1
Đáp án: \(\frac{{10{x^2} + 10}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}\) Giải thích các bước giải: \(\begin{array}{l}\frac{{3x + 2}}{{{x^2} – 2x + 1}} – \frac{6}{{{x^2} – 1}} – \frac{{3x – 2}}{{{x^2} + 2x + 1}}(x \ne 1, – 1)\\ = \frac{{(3x + 2){{(x + 1)}^2} – 6({x^2} – 1) – (3x – 2){{(x – 1)}^2}}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}\\ = \frac{{10{x^2} + 10}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}\end{array}\) Bình luận
Đáp án:
\(\frac{{10{x^2} + 10}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}\)
Giải thích các bước giải:
\(\begin{array}{l}
\frac{{3x + 2}}{{{x^2} – 2x + 1}} – \frac{6}{{{x^2} – 1}} – \frac{{3x – 2}}{{{x^2} + 2x + 1}}(x \ne 1, – 1)\\
= \frac{{(3x + 2){{(x + 1)}^2} – 6({x^2} – 1) – (3x – 2){{(x – 1)}^2}}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}\\
= \frac{{10{x^2} + 10}}{{{{(x – 1)}^2}{{(x + 1)}^2}}}
\end{array}\)