Tính 3/7×16/33+16/33×4/7 (làm bằng 2 cách) 04/12/2021 Bởi Savannah Tính 3/7×16/33+16/33×4/7 (làm bằng 2 cách)
Đáp án: c1: 3/7×16/33+16/33×4/7 =16/33x(3/7+4/7) =16/33×1 =16/33 c2: 3/7×16/33+16/33×4/7 =3×16/7×33+16×4/33×7 =48/231+64/231 =16/77+64/231 =16×3/77×3+64/231 =48/231+64/231 =112/231 =16/33 HỌC TỐT~~ Bình luận
$C_1:\dfrac{3}{7}×$ $\dfrac{16}{33}$ $+\dfrac{16}{33}$ $×\dfrac{4}{7}$ $=\dfrac{48}{231}+\dfrac{64}{231}$ $=\dfrac{112}{231}=\dfrac{16}{33}$ $C_2:\dfrac{3}{7}×$ $\dfrac{16}{33}$ $+\dfrac{16}{33}$ $×\dfrac{4}{7}$ $=\dfrac{16}{33}×(\dfrac{3}{7}$ $+\dfrac{4}{7})$ $=\dfrac{16}{33}×1$ $=\dfrac{16}{33}$ Bình luận
Đáp án:
c1:
3/7×16/33+16/33×4/7
=16/33x(3/7+4/7)
=16/33×1
=16/33
c2:
3/7×16/33+16/33×4/7
=3×16/7×33+16×4/33×7
=48/231+64/231
=16/77+64/231
=16×3/77×3+64/231
=48/231+64/231
=112/231
=16/33
HỌC TỐT~~
$C_1:\dfrac{3}{7}×$ $\dfrac{16}{33}$ $+\dfrac{16}{33}$ $×\dfrac{4}{7}$
$=\dfrac{48}{231}+\dfrac{64}{231}$
$=\dfrac{112}{231}=\dfrac{16}{33}$
$C_2:\dfrac{3}{7}×$ $\dfrac{16}{33}$ $+\dfrac{16}{33}$ $×\dfrac{4}{7}$
$=\dfrac{16}{33}×(\dfrac{3}{7}$ $+\dfrac{4}{7})$
$=\dfrac{16}{33}×1$
$=\dfrac{16}{33}$