Tính A= 1/17+ 1/170 + 3/70 + 2/35 + 1/20 08/07/2021 Bởi Faith Tính A= 1/17+ 1/170 + 3/70 + 2/35 + 1/20
`A= 1/20 + 2/35 + 3/70 + 1/170 + 1/17` `A= 1/4.5 + 2/5.7 + 3/7.10 + 1/170 + 1/17` `A= 1/4 – 1/5 + 1/5 – 1/7 + 1/7- 1/10 + 1/170 + 1/17` `A= 1/4 – 1/10 + 1/170 + 1/17` `A= 3/20 + 1/170 + 1/17` `A= 53/240 + 1/17` `A=73/340` Vậy `A= 73/340` Bình luận
`A= 1/17+ 1/170 + 3/70 + 2/35 + 1/20` `⇔A=(140)/(2380)+(14)/(2380)+(102)/(2380)+(136)/(2380)+(119)/(2380)` `⇔A=(140+14+102+136+119)/(2380)` `⇔A=(511)/(2380)` `⇔A=(73)/(340)` Bình luận
`A= 1/20 + 2/35 + 3/70 + 1/170 + 1/17`
`A= 1/4.5 + 2/5.7 + 3/7.10 + 1/170 + 1/17`
`A= 1/4 – 1/5 + 1/5 – 1/7 + 1/7- 1/10 + 1/170 + 1/17`
`A= 1/4 – 1/10 + 1/170 + 1/17`
`A= 3/20 + 1/170 + 1/17`
`A= 53/240 + 1/17`
`A=73/340`
Vậy `A= 73/340`
`A= 1/17+ 1/170 + 3/70 + 2/35 + 1/20`
`⇔A=(140)/(2380)+(14)/(2380)+(102)/(2380)+(136)/(2380)+(119)/(2380)`
`⇔A=(140+14+102+136+119)/(2380)`
`⇔A=(511)/(2380)`
`⇔A=(73)/(340)`