tính a,120/40^3 b,(0,25)^3. 512 c , 2^15. 9^4/ 6^6. 8^3 15/07/2021 Bởi Alaia tính a,120/40^3 b,(0,25)^3. 512 c , 2^15. 9^4/ 6^6. 8^3
a.($\frac{120}{40})^{3}$ = $3^{3}$ = 27 b. ( 0,25 )$^{3}$ . 512 = ( 0,25 )$^{3}$ . $8^{3}$ = ( 0,25 . 8 )$^{3}$ = $2^{3}$ = 8 c. $\frac{2^{15} . 9^{4} }{6^{6} . 8^{3}}$ = $\frac{2^{15} . 3^{8}}{2^{6} . 3^{6} . 2^{9}}$ = $3^{2}$ = 9 Bình luận
a, $\frac{120^3}{40^3}=$$(\frac{120}{40})^3=3^3=27$ b, (0,25)³.512 =$\frac{1}{64}$.512 =8 c, $\frac{2^{15}.9^4}{6^6.8^3}=$ $\frac{2^{15}.3^{8}}{2^6.3^6.2^{9}}=3^2=9$ Bình luận
a.($\frac{120}{40})^{3}$
= $3^{3}$
= 27
b. ( 0,25 )$^{3}$ . 512
= ( 0,25 )$^{3}$ . $8^{3}$
= ( 0,25 . 8 )$^{3}$
= $2^{3}$
= 8
c. $\frac{2^{15} . 9^{4} }{6^{6} . 8^{3}}$
= $\frac{2^{15} . 3^{8}}{2^{6} . 3^{6} . 2^{9}}$
= $3^{2}$
= 9
a, $\frac{120^3}{40^3}=$$(\frac{120}{40})^3=3^3=27$
b, (0,25)³.512
=$\frac{1}{64}$.512
=8
c, $\frac{2^{15}.9^4}{6^6.8^3}=$ $\frac{2^{15}.3^{8}}{2^6.3^6.2^{9}}=3^2=9$