Tính a) 15/27-2/9 b)7/5-2/3 c)10/13-15/39 d)4-2/7 Phép trừ phân số ạ. 28/11/2021 Bởi Claire Tính a) 15/27-2/9 b)7/5-2/3 c)10/13-15/39 d)4-2/7 Phép trừ phân số ạ.
$\text{Giải thích các bước giải:}$ $a, \dfrac{15}{27} – \dfrac{2}{9}$ $= \dfrac{15}{27} – \dfrac{6}{27}$ $= \dfrac{9}{27}$ $= \dfrac{1}{3}$ $b, \dfrac{7}{5} – \dfrac{2}{3}$ $= \dfrac{21}{15} – \dfrac{10}{15}$ $= \dfrac{11}{15}$ $c, \dfrac{10}{13} – \dfrac{15}{39}$ $= \dfrac{30}{39} – \dfrac{15}{39}$ $= \dfrac{15}{39}$ $d, 4 – \dfrac{2}{7}$ $= \dfrac{28}{7} – \dfrac{2}{7}$ $= \dfrac{26}{7}$ $\text{Chúc bạn học tốt !}$ Bình luận
Đáp án: a) $\dfrac{15}{27}$- $\dfrac{2}{9}$ = $\dfrac{15}{27}$ – $\dfrac{6}{27}$ = $\dfrac{9}{15}$ = $\dfrac{3}{5}$ b) $\dfrac{7}{5}$ – $\dfrac{2}{3}$ = $\dfrac{21}{15}$ – $\dfrac{10}{15}$ = $\dfrac{11}{15}$ c)$\dfrac{10}{13}$ – $\dfrac{15}{39}$ = $\dfrac{30}{39}$ – $\dfrac{15}{39}$ = $\dfrac{15}{39}$ = $\dfrac{5}{13}$ d) 4-$\dfrac{2}{7}$ = $\dfrac{28}{7}$- $\dfrac{2}{7}$ = $\dfrac{26}{7}$ Giải thích các bước giải: Bình luận
$\text{Giải thích các bước giải:}$
$a, \dfrac{15}{27} – \dfrac{2}{9}$
$= \dfrac{15}{27} – \dfrac{6}{27}$
$= \dfrac{9}{27}$
$= \dfrac{1}{3}$
$b, \dfrac{7}{5} – \dfrac{2}{3}$
$= \dfrac{21}{15} – \dfrac{10}{15}$
$= \dfrac{11}{15}$
$c, \dfrac{10}{13} – \dfrac{15}{39}$
$= \dfrac{30}{39} – \dfrac{15}{39}$
$= \dfrac{15}{39}$
$d, 4 – \dfrac{2}{7}$
$= \dfrac{28}{7} – \dfrac{2}{7}$
$= \dfrac{26}{7}$
$\text{Chúc bạn học tốt !}$
Đáp án:
a) $\dfrac{15}{27}$- $\dfrac{2}{9}$ = $\dfrac{15}{27}$ – $\dfrac{6}{27}$ = $\dfrac{9}{15}$ = $\dfrac{3}{5}$
b) $\dfrac{7}{5}$ – $\dfrac{2}{3}$ = $\dfrac{21}{15}$ – $\dfrac{10}{15}$ = $\dfrac{11}{15}$
c)$\dfrac{10}{13}$ – $\dfrac{15}{39}$ = $\dfrac{30}{39}$ – $\dfrac{15}{39}$ = $\dfrac{15}{39}$ = $\dfrac{5}{13}$
d) 4-$\dfrac{2}{7}$ = $\dfrac{28}{7}$- $\dfrac{2}{7}$ = $\dfrac{26}{7}$
Giải thích các bước giải: