Tính a) 2 Div 3 – 2 Mod 3 + 3 Div 2 – 3 Mod 2 b) 1/2 – 2 * 7 Mod 2 – 8 Div 4 * 4 c) (12+5) Mod 3 – (2*8) Div 5 – 1 d) 5/4 – 4*5 Div 7 + 15 Mod 3

0 bình luận về “Tính a) 2 Div 3 – 2 Mod 3 + 3 Div 2 – 3 Mod 2 b) 1/2 – 2 * 7 Mod 2 – 8 Div 4 * 4 c) (12+5) Mod 3 – (2*8) Div 5 – 1 d) 5/4 – 4*5 Div 7 + 15 Mod 3”

1. a/ 2 Div 3 – 2 Mod 3 + 3 Div 2 – 3 Mod 2 = 0-2+1-1=-2

   b/ 1/2 – 2 * 7 Mod 2 – 8 Div 4 * 4 = 1/2 – 0 -2*4 = -7.5

   c) (12+5) Mod 3 – (2*8) Div 5 – 1 = 17 mod 3 – 16 div 5 – 1 = 2 – 3 – 1 = -2

   d/ 5/4 – 4*5 Div 7 + 15 Mod 3 = 5/4 – 2 +  0 = -0,75

   Trả lời

2. a) 2 div 3 – 2 mod 3 + 3 div 2 – 3 mod 2

   = 0 – 2 + 1 – 1 = -2

   b) 1/2 – 2*7 mod 2 – 8 div 4 * 4

   = 1/2 – 12 mod 2 – 2 * 4 

   = 1/2 – 0 0 8

   = 1/2 – 8

   c) (12+5) mod 3 – (2*8) div 5 – 1

   = 17 mod 3 – 16 div 5 – 1

   = 2 – 3 – 1 

   = -2

   d) 5/4 – 4*5 div 7 + 15 mod 3

   = 5/4 – 20 div 7 + 0

   = 5/4 – 2 + 0

   = 5/4 – 2

   Trả lời