Toán tính a biết A= (1- 1/2) . (1-1/3). (1-1/4) … ) -( 1/2016) 16/09/2021 By Eden tính a biết A= (1- 1/2) . (1-1/3). (1-1/4) … ) -( 1/2016)
`A = ( 1 – 1/2 ) . ( 1 – 1/3 ) . ( 1 – 1/4 ) …. . ( 1 – 1/2016 )` `= 1/2 . 2/3 . 3/4 …. 2015/2016` `=` $\frac{1 . 2 . 3 … 2015}{2 . 3 . 4 …. 2016}$ `= 1/2016` Trả lời
Đáp án: `A=1/2016` Giải thích các bước giải: `A= (1- 1/2) . (1-1/3). (1-1/4) … (1- 1/2016)``A=(2/2-1/2)(3/3-1/3)(4/4-1/4)…(2016/2016-1/2016)``A=1/2 . 2/3 . 3/4 . … . 2015/2016``A=(1.2.3…2015)/(2.3.4…2016)``A=1/2016`Vậy `A=1/2016` Trả lời
`A = ( 1 – 1/2 ) . ( 1 – 1/3 ) . ( 1 – 1/4 ) …. . ( 1 – 1/2016 )`
`= 1/2 . 2/3 . 3/4 …. 2015/2016`
`=` $\frac{1 . 2 . 3 … 2015}{2 . 3 . 4 …. 2016}$
`= 1/2016`
Đáp án:
`A=1/2016`
Giải thích các bước giải:
`A= (1- 1/2) . (1-1/3). (1-1/4) … (1- 1/2016)`
`A=(2/2-1/2)(3/3-1/3)(4/4-1/4)…(2016/2016-1/2016)`
`A=1/2 . 2/3 . 3/4 . … . 2015/2016`
`A=(1.2.3…2015)/(2.3.4…2016)`
`A=1/2016`
Vậy `A=1/2016`