tính đạo hàm bậc 2 của hàm số sau: y=$\sqrt{2x-x^{3}}$

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1. Đáp án: `((-6x))/(2sqrt(2x-x^3))-((2-3x^2)^2)/(4.(2x-x^3).(sqrt(2x-x^3)))`

   Giải thích các bước giải:

   `y^’=(sqrt(2x-x^3))^’=((2x-x^3)^’)/(2sqrt(2x-x^3))=(2-3x^2)/(2sqrt(2x-x^3))`

   `=> y”=((2-3x^2)/(2sqrt(2x-x^3)))^’=((2-3x^2)^’.(2sqrt(2x-x^3))-(2-3x^2).(2sqrt(2x-x^3))^’)/((2sqrt(2x-x^3))^2)`

   `=((-6x).(2sqrt(2x-x^3))-(2-3x^2).(2.((2x-x^3)^’)/(2sqrt(2x-x^3))))/((2sqrt(2x-x^3))^2)`

   `=((-6x).(2sqrt(2x-x^3))-(2-3x^2).(2.((2-3x^2))/(2sqrt(2x-x^3))))/((2sqrt(2x-x^3))^2)`

   `=((-6x).(2sqrt(2x-x^3))-(((2-3x^2)^2)/(sqrt(2x-x^3))))/((2sqrt(2x-x^3))^2)`

   `=((-6x).(2sqrt(2x-x^3)))/((2sqrt(2x-x^3))^2)-(((2-3x^2)^2)/(sqrt(2x-x^3)))/((2sqrt(2x-x^3))^2)`

   `=((-6x))/(2sqrt(2x-x^3))-(((2-3x^2)^2)/(sqrt(2x-x^3)))/(4.(2x-x^3))`

   `=((-6x))/(2sqrt(2x-x^3))-((2-3x^2)^2)/(4.(2x-x^3).(sqrt(2x-x^3)))`

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